The Student Room Group
Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>

AQA A2 MM2B Mechanics 2 – 27th June 2016 [Exam Discussion Thread]

Scroll to see replies

How did everyone find it
That 8 marker... 😂
I ****ed up ggwp
Anyone get 3mu/4 for the tantheta
And 3.5m or something like that for the last question.
Original post by Pentaquark
Anyone get 3mu/4 for the tantheta
And 3.5m or something like that for the last question.

You were supposed to add 4m to that
Original post by C0balt
You were supposed to add 4m to that

Ahhh at least i was on the right track lol
I found somwthing like 18m from R then took away 15m (R to Q) :s
I hope i get method marks haha i had like 3 pages of working for it.
Anyone get root 5ag for the 4 marker least value of mu.

Grade boundaries for an A* anyone?
65 last year. I think similar to 2015 maybe a higher ??
Original post by Pentaquark
Anyone get 3mu/4 for the tantheta
And 3.5m or something like that for the last question.

I got 3.58 of the distance from A but they wanted the distance from Q so i got 7.58
Reply 107
Avatar for RockyG
RockyG
1
Original post by Pentaquark
Anyone get root 5ag for the 4 marker least value of mu.

Grade boundaries for an A* anyone?
65 last year. I think similar to 2015 maybe a higher ??


i got root 5ag, did you say tension at the top was greater than 0?
I got tan(theta)=(1-2u^2)/4u
I drew the ladder diagram incorrectly, would I get consequential for the part afterwards?
Some more of what i can remember. Put me out of misery guys haha
Tension 6g
Angle theta was 41.4 degrees
Radius 3. Something m idk. I just resolved horizbtally.

Least value of tension I just put T=0
Then u = root 5ag :/

Ladder 3/4 mu, got a quadratic with tantheta
Tried to simplify it down. Probably incorrectly.
Ive probably cancelled wrong or somethibg
I resolved vertically, horizontally moments about base. Lol idk


Differential equation i wasnt sure. The constant lambda cancels right?
V= Ue^gt

12.7m/s for somwthing
T=1.26s for force when due south.

Centre of mass angle like 16.1 degrees??
I just used the 15cm and the other cm.

i hope i havent dropped too many D:
Method marks will save me haha
(edited 7 years ago)
Reply 111
Avatar for RockyG
RockyG
1
Original post by ashwinderk
I got tan(theta)=(1-2u^2)/4u


damn i left it as 1/4u -U/2
+1 Git this but others got something different. Hopefully we're right!
Original post by RockyG
damn i left it as 1/4u -U/2

Yeh, i think they will allow that
Original post by C0balt
You were supposed to add 4m to that


I got 7.5m for the last question, where P had moved 3.5m too btw
Original post by benjammy
I got 7.5m for the last question, where P had moved 3.5m too btw

I got 7.58
Reply 116
Avatar for RockyG
RockyG
1
Original post by ashwinderk
Yeh, i think they will allow that


awesome =)
Anyone get like 105° for centre of mass angle?
Centre of mass angle 16.7 or something? Last question 7.5 something? For tan I got -1/2u, don't know how
Reply 119
Avatar for Jm098
Jm098
2
I got radius as 2.89?

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you