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Edexcel S2 - 27th June 2016 AM

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Original post by igotohaggerston
How many marks was the P(7<R<10) question


What was the answer to this question????!
Original post by iMacJack
Does anyone know if @kprime2 is DOIN model answers


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He said he would in another thread, probably tomorrow.
Original post by Ayman!
Well, S2 is sort of unpredictable. That mark would easily get you a solid A with 84+ UMS on IAL June 14 or June 15, but would be a high B on UK 15 or IAL Jan 16... I say relax until the grade boundaries are released - even then, you could still be severely underestimating yourself! :biggrin:


When are grade boundaries released???
Original post by Ayman!
Well, S2 is sort of unpredictable. That mark would easily get you a solid A with 84+ UMS on IAL June 14 or June 15, but would be a high B on UK 15 or IAL Jan 16... I say relax until the grade boundaries are released - even then, you could still be severely underestimating yourself! :biggrin:


I did calculate the absolute minimum I could get. I think I could get up to 69 (that would be great). Last year I was a lot more confident about what I was going to get. Got 198/200 in C3 and C4 so no problem there for A* in normal maths and I thought FM was in the bag as well...
Original post by Dentistry101
What was the answer to this question????!


I just did the area so (10-7)*probability. I can't rightly remember what the probability was, maybe 1/4? If so it would just be 3/4.
0.5
Original post by igotohaggerston
0.5

Was that a reply to me??
Original post by Jack_Linaker
I just did the area so (10-7)*probability. I can't rightly remember what the probability was, maybe 1/4? If so it would just be 3/4.



But the distribution was U~[5,9] so would it not be 2 x 0.25??
The distribution was [5,9] so it would've been 0.25*(9-7)=0.5
Original post by ISAAQAHELP
THIS IS THE QUESTION FOR THE normal APPROX.

X-B(N,0.2) USING NORMAL APPROX AND GIVEN THAT P(X>55)=0.0401
FIND N

AND ANSWER:
X-B[N,0.2]= W-N[X,Y"] X IS MEAN Y" IS VARIANCE " MEANS SQUARED

P(X>55)=P[W>55.5)=P(Z>([55.5-X]/Y)=0.0401

P(Z<([55.5-X]/Y)=1-0.0401=0.9599

USING TABLE

(55.5-X)/Y=1.75
55.5-X=1.75Y
1.75Y+X=55.5 NOW USING THE BINOMIAL PARAMETERS
WE CAN FIND Y AND X IN TERMS OF N
X=0.2N
Y"=0.2*0.8N Y"=0.16N Y=0.4N! WHERE !=SQUARE ROOT
SO 1.75(0.4N!)+0.2N =55.5
0.7N!+0.2N=55.5
0.2N+0.7N!-55.5=0 NOW SOLVE THIS USING QUADRATIC FORMULA
YOU GET N!=15 OR (-18.5)
SO N = 225 OR 342.25 BUT WE ARE DEALING STUDENTS
SO N=225 ONLY
don't KNOW WHY PEOPLE ARE GETTING 200



I know I did wrong. I used 55 not 55.5 , worked out 223 and 340. I didn't reject 340..... How many marks I will lost?
Original post by Dentistry101
But the distribution was U~[5,9] so would it not be 2 x 0.25??


God dammit you're right fml
Could someone link me the unofficial scheme?
Original post by ShowMeUnofficial
Could someone link me the unofficial scheme?


http://www.thestudentroom.co.uk/attachment.php?attachmentid=557191&d=1467024133
Original post by AlexFrangos
Sure. How did you find the paper?




I think its pretty easy. I just spent 45 minutes to finish the paper.

The only thing I'm not sure about is the question concerning car test, i dun know if its talking about 20 cars or 54 cars.
For the normal approximation question i forgot to use sq rt of np(1-p). how many marks do you think i lost?
Who else thought question 8 was quite cute? :smile:
Original post by hank_the_tank
I think its pretty easy. I just spent 45 minutes to finish the paper.

The only thing I'm not sure about is the question concerning car test, i dun know if its talking about 20 cars or 54 cars.


I made a mistake in the critical region question, i found X>=11 rather X>=9 and so the next parts of that question went wrong. Do you think i will lose all the marks in that question?
[QUOTE=cogito.;66151095]Isn't Q1 E(X) is about 1.41?

Yeah it is 1.41, that's the only mistake that was made on the answers
Honestly why does the poll suggest people found it hard? This was an average S2 paper and probably it will be like 70 for an A*

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