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AQA Physics PHYA5 - 28th June 2016 [Exam Discussion Thread]

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Original post by ahlam H
Did anyone get 2100J and 2500J for the last 2 questions on nuclear physics


What were those questions?


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Original post by ahlam H
Did anyone get 2100J and 2500J for the last 2 questions on nuclear physics


Yes that's right


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Original post by nnblccz
Swear I got 1.8x10^11, which is basically the specific charge of an electron


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Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m
Original post by the_chosen_one97
Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m


Or you can use the 2V/B^2r^2 because they gave all data and answer was 1.9*10^11


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Original post by BigDaddy97
Yes that's right


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i think i got them the other way round? wasnt specific heat capacity 2120? and the energy was 2490?
Original post by the_chosen_one97
Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m


Erm you didn't have v - the velocity - you had the potential through which they are accelerated


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Original post by BigDaddy97
Or you can use the 2V/B^2r^2 because they gave all data and answer was 1.9*10^11
Yep , I got this

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Yep I got this
Original post by Ac19951
1.22x10^8 AU for the last question in Astrophysics anyone? I think i forgot to square root my answer.

Also what did you guys write for the first part of the CCD question? Regarding structure.


it was 2.4x10^14 AU
Surprisingly not too bad. Think I've made a few mistakes but that was a nice paper regardless
128MeV???????
Original post by aelahi23
Found the exam to easy quite. I did turning points for optional module

although one question threw me off, the 4 mark question in turning points that asked to find specific charge I got 2.1 * 10^8 what did other people get?

since F=Bev and F= Mv^2/r
I did equated them to each other then rearranged to get
e/m = v/Br

"v" mean velocity
"V" means PD

To find v (velocity) I did v=V/Br

so subbed in the v=V/Br into e/m = v/Br to get rid of velocity from the equation to get e/m= V/Br/Br
which simplified to e/m= V/ B^2 * r^2
Is that correct?

Section A was very easy so I don't have any queries about that


I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
Original post by Sid1234
it was 2.4x10^14 AU


Me too!! Thank god :biggrin:
Original post by Mango Milkshake
128MeV???????


YES !
I wrote about Rutherford alpha scattering, wbu?
Original post by Mango Milkshake
128MeV???????


127.24 i got o.O
Original post by cowie
What were those questions?


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It was about the specfic capacity and latent for ice and water where the ice was raised from -25 to 0 degrees celcius
Original post by txnilxnur
I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao


Both methods will get the marks chill


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Original post by Sid1234
it was 2.4x10^14 AU


i got this as well
anyone can post the solution for turning point ?
Original post by txnilxnur
I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao


No you can't do it that way - you're using the electron charge and mass from the formula booklet which they wouldn't have had at the time! The question made it clear: use THIS data


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