Found the exam to easy quite. I did turning points for optional module
although one question threw me off, the 4 mark question in turning points that asked to find specific charge I got 2.1 * 10^8 what did other people get?
since F=Bev and F= Mv^2/r I did equated them to each other then rearranged to get e/m = v/Br
"v" mean velocity "V" means PD
To find v (velocity) I did v=V/Br
so subbed in the v=V/Br into e/m = v/Br to get rid of velocity from the equation to get e/m= V/Br/Br which simplified to e/m= V/ B^2 * r^2 Is that correct?
Section A was very easy so I don't have any queries about that
I used the equation eV = 1/2 mv^2 Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11. I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
I used the equation eV = 1/2 mv^2 Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11. I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
I used the equation eV = 1/2 mv^2 Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11. I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
No you can't do it that way - you're using the electron charge and mass from the formula booklet which they wouldn't have had at the time! The question made it clear: use THIS data