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Maths year 11

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Reply 560
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z_o_e
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11
Original post by RDKGames
The blue angles are the interior angles of the two pentagons. You can find the red angles because it's a parallelogram where opposite angles are equal, and all of these add up to 360. Black angle + red angle should make up the interior angle of the regular pentagon, thus allowing you to find angle AEH.

Pentagons.PNG




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Original post by z_o_e


Why did you mark blue angles 180? Wouldn't make sense for two angles to add up to 360 with a quadtrilateral. Blue angles are the interior angles of the pentagon's if you can see it.
Reply 562
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Original post by RDKGames
Why did you mark blue angles 180? Wouldn't make sense for two angles to add up to 360 with a quadtrilateral. Blue angles are the interior angles of the pentagon's if you can see it.

Is it 90?

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Original post by z_o_e


No...

Pentagons.PNG
Original post by z_o_e


Those two angles can't be 180 - 180 degrees is a straight line and also all four angles within the quadrilateral must add up to 360 degrees therefore it's impossible to have two angles at 180 degrees.
Reply 565
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Original post by RDKGames
No...

Pentagons.PNG


Omg yes I got 108

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Reply 566
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Original post by z_o_e


Correct, now you can find the black angle which is the one you need.
Reply 568
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Original post by RDKGames
Correct, now you can find the black angle which is the one you need.


I got 108

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Original post by z_o_e


Yeah that's the interior angle of the pentagon, the red and the black angles make up one interior angle and you know the red angle, so you can take one away from the other and get your black angle.
Reply 570
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Original post by RDKGames
Yeah that's the interior angle of the pentagon, the red and the black angles make up one interior angle and you know the red angle, so you can take one away from the other and get your black angle.


36

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Original post by z_o_e


Yep. :smile:
Reply 572
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Original post by RDKGames
Yep. :smile:


Thank youuu so much

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Reply 573
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Original post by RDKGames
Yep. :smile:


Is this 28*14

Find the area of the semi circles and subtract them from the original answer?



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Reply 574
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Original post by RDKGames
Yep. :smile:


Is this 28*14

Find the area of the semi circles and subtract them from the original answer?
.


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Original post by z_o_e
Is this 28*14

Find the area of the semi circles and subtract them from the original answer?
.


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That's the correct method but trapezium's area is not quite right. Recall your trapezium area to be 12(a+b)⋅h\frac{1}{2}(a+b)\cdot h
(edited 7 years ago)
Reply 576
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Original post by RDKGames
That's the correct method but trapezium's area is not quite right. Recall your trapezium area to be 12(a+b)⋅h\frac{1}{2}(a+b)\cdot h


OH YESS :smile:)
I GOT THE HANG OF THIS YAAY

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Original post by z_o_e
OH YESS :smile:)
I GOT THE HANG OF THIS YAAY

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Also I'd like to just say that if you're a visual learner, and colours help you identify different important things in a question such as that double pentagon one there, then I'd suggest you use them in the future. I believe you can also use them in the exam but ask your teacher just to be sure. :smile:
Reply 578
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z_o_e
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11
Original post by RDKGames
Also I'd like to just say that if you're a visual learner, and colours help you identify different important things in a question such as that double pentagon one there, then I'd suggest you use them in the future. I believe you can also use them in the exam but ask your teacher just to be sure. :smile:


Thank youu:smile:)



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Original post by z_o_e


Correct.

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