Maths year 11

Ah good, then this should be straight forward.

If you label the angle at the tower, lets say $\theta$ (called theta), then you know that $tan\theta$ is the opposite side divided by the adjacent side, with opposite being 4.5 and adjacent being 2.1 as you can see. You can find the actual angle by doing inverse tan. Of course, this angle is not the bearing because bearings are measured from the North, therefore you need to find the other angle long that line by doing $180-\theta$, and that should give you the bearing. Don't forget bearings are shown as 3 digits.

So do I find the hypotenuse

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Well realistically you have choices, you can use the hypoteneuse and work with either sine or cosine, or you can use the two sides of the triangle which would require you to use tan (refer back to what I said if you want to use tan). You already know the hypoteneuse though, you found it in the previous part.

Well realistically you have choices, you can use the hypoteneuse and work with either sine or cosine, or you can use the two sides of the triangle which would require you to use tan (refer back to what I said if you want to use tan). You already know the hypoteneuse though, you found it in the previous part.

Here

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Correct. You can now use this to find the bearing as you know the angles on a straight line add up to 180.

115

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Yep!

Yep!

Yep!

I did something wrong can't figure it out.,

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AC is just hypotenuse, and since you are given the side lengths, it's basic pythagoras to find it.

Did these


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37 is right but the bearing is wrong because that would mean you are measuring it anticlockwise.

Bearing tell us that they are measured clockwise from the north line as a 3 digit number.

So the answer is 037?

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No. I meant I agree with your working up until you get 37 degrees. Think about how you can use that to get the bearing by measuring it clockwise from the north.

217

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Correct.