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Maths year 11

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Well done. :smile:

Have a go at the other question's I've posted.
Original post by z_o_e
How did this go?

Shall I added 5 root 4 & root 6?



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Is it POSSIBLE to make 55+65\sqrt{5} + \sqrt{6} any simpler by any means of addition? If not, then no you don't add them.
Reply 1322
Original post by RDKGames
Is it POSSIBLE to make
Unparseable latex formula:

5\root{5} + \sqrt{6}

any simpler by any means of addition? If not, then no you don't add them.


So this is the final answer ?


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Original post by z_o_e
How did this go?

Shall I added 5 root 4 & root 6?



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Also, show me how you got 32+233\sqrt2 + 2\sqrt3 to equal 555\sqrt5?
Original post by z_o_e
So this is the final answer ?


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No. That's just simply a wrong answer. Refer to my post above ^
Reply 1325
Original post by RDKGames
Also, show me how you got 32+233\sqrt2 + 2\sqrt3 to equal 555\sqrt5?


I added 3 + 2 inside and outside the root which got me 5 r 5

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Original post by z_o_e
I added 3 + 2 inside and outside the root which got me 5 r 5

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What surd rule did you use for that?
Reply 1327
Original post by RDKGames
What surd rule did you use for that?


I didn't use a rule

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Original post by z_o_e
I didn't use a rule

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Precisely why your answer is wrong. You just guessed that's how it works.

32+233\sqrt2 + 2\sqrt3 cannot be simplified any further.
Reply 1329
Original post by RDKGames
Precisely why your answer is wrong. You just guessed that's how it works.

32+233\sqrt2 + 2\sqrt3 cannot be simplified any further.


So what do I do to find the final answer?

There's nothing else really left I think that's the final answer.

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Original post by z_o_e
So what do I do to find the final answer?

There's nothing else really left I think that's the final answer.

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Exactly. The final answer is indeed 6+23+32+6\sqrt6 + 2\sqrt3 + 3\sqrt 2 + 6
Reply 1331
Original post by RDKGames
Exactly. The final answer is indeed 6+23+32+6\sqrt6 + 2\sqrt3 + 3\sqrt 2 + 6


So surds like that cannot be added?

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Original post by z_o_e
So surds like that cannot be added?

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No. Square root of a number is the same as raising that number to the power of 1/2. This means that you would essentially be adding something like a12+b12a^{\frac{1}{2}}+b^{\frac{1}{2}} into (a+b)12(a+b)^{\frac{1}{2}} which doesn't make sense because a and b are different bases and laws of indices do not work that like that.
Reply 1333
Original post by RDKGames
No. Square root of a number is the same as raising that number to the power of 1/2. This means that you would essentially be adding something like a12+b12a^{\frac{1}{2}}+b^{\frac{1}{2}} into (a+b)12(a+b)^{\frac{1}{2}} which doesn't make sense because a and b are different bases and laws of indices do not work that like that.


Oh thanks


And how's this



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Original post by z_o_e
Oh thanks


And how's this



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Okay hang on. The method overall is correct. Check the numerator multiplication on the first line, and then check if the denominator on the second line is truly the same as (2+610)(2610)(2+6\sqrt{10})(2-6\sqrt{10})
Reply 1335
Original post by RDKGames
Okay hang on. The method overall is correct. Check the numerator multiplication on the first line, and then check if the denominator on the second line is truly the same as (2+610)(2610)(2+6\sqrt{10})(2-6\sqrt{10})


I don't see anything wrong?

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Original post by z_o_e
I don't see anything wrong?

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Okay. For the numerator, you have 8 on the first fraction and the (2 take 6 root 10) on the second, when you multiply the two fractions, you multiply the two numerators. So 8 times (2 take 6 root 10).

For denominator, expand the brackets and see what you get. Compare this to what you've written.
Reply 1337
Original post by RDKGames
Okay. For the numerator, you have 8 on the first fraction and the (2 take 6 root 10) on the second, when you multiply the two fractions, you multiply the two numerators. So 8 times (2 take 6 root 10).

For denominator, expand the brackets and see what you get. Compare this to what you've written.


This?


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Yeah you fixed the numerator. Now fix the denominator. Expand it and see what you get.
Reply 1339
Original post by RDKGames
Yeah you fixed the numerator. Now fix the denominator. Expand it and see what you get.


I got this


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