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Maths year 11

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Original post by z_o_e


Correct. You can make it even more simpler though. :smile:
Reply 1341
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Original post by RDKGames
Correct. You can make it even more simpler though. :smile:


Yeussssss.
I'll have 2 more questions please :smile:

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Original post by z_o_e
Yeussssss.
I'll have 2 more questions please :smile:

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Sure, after you finish fully simplifying THAT one.
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Original post by RDKGames
Sure, after you finish fully simplifying THAT one.


Simplify that?
I'm not really sure.

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Reply 1344
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Original post by RDKGames
Sure, after you finish fully simplifying THAT one.


Simplify that?
I'm not really sure..

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Original post by z_o_e
Simplify that?
I'm not really sure..

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I'll give you an example; how can I simplify something like 2+2a2\displaystyle \frac{2+2a}{2}?
Reply 1346
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Original post by RDKGames
I'll give you an example; how can I simplify something like 2+2a2\displaystyle \frac{2+2a}{2}?


Cancel the top and bottom 2 and you're left with 2a

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Original post by z_o_e
Cancel the top and bottom 2 and you're left with 2a

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Oh dear, you're gonna need to practice your fractions.

Gonna skip the encouragement:

16−4810−356\displaystyle \frac{16-48\sqrt{10}}{-356}

Divide/multiply (doesn't matter which) top and bottom by -1

4810−16356\displaystyle \frac{48\sqrt{10} - 16}{356}

Factorise the numerator as much as you can:

16(310−1)356\displaystyle \frac{16(3\sqrt{10}-1)}{356}

You can rewrite this as:

16356(310−1)\displaystyle \frac{16}{356}(3\sqrt{10}-1)

See how far you can simplify the fraction. The simplest it goes is:

489(310−1)\displaystyle \frac{4}{89}(3\sqrt{10}-1)

So final answer would be that. Or you can also rewrite it as:

4(310−1)89\displaystyle \frac{4(3\sqrt{10}-1)}{89}

which leads to

1210−489\displaystyle \frac{12\sqrt{10}-4}{89}
Original post by z_o_e
Cancel the top and bottom 2 and you're left with 2a

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Add these fractions:

12+12 \frac{1}{2}+\frac{1}{2}

12+13\frac{1}{2}+\frac{1}{3}

52+15\frac{5}{2}+\frac{1}{5}

34+72\frac{3}{4}+\frac{7}{2}

62+26\frac{6}{2}+\frac{2}{6}

b2+aa\frac{b}{2}+\frac{a}{a}

ab+cd\frac{a}{b}+\frac{c}{d}

a+12+12\frac{a+1}{2}+\frac{1}{2}

ab+1+12\frac{a}{b+1}+\frac{1}{2}

2a2b+2+28\frac{2a}{2b+2}+\frac{2}{8}
(edited 7 years ago)
Reply 1349
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Original post by RDKGames
Add these fractions:

12+12 \frac{1}{2}+\frac{1}{2}

12+13\frac{1}{2}+\frac{1}{3}

52+15\frac{5}{2}+\frac{1}{5}

34+72\frac{3}{4}+\frac{7}{2}

62+26\frac{6}{2}+\frac{2}{6}

b2+aa\frac{b}{2}+\frac{a}{a}

ab+cd\frac{a}{b}+\frac{c}{d}

a+12+12\frac{a+1}{2}+\frac{1}{2}

ab+1+12\frac{a}{b+1}+\frac{1}{2}

2a2b+2+28\frac{2a}{2b+2}+\frac{2}{8}


I'm not sure about a and b I think after question 6

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Original post by z_o_e
I'm not sure about a and b I think after question 6

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How did you add the previous fractions? You add these ones just the same way.
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Original post by RDKGames
How did you add the previous fractions? You add these ones just the same way.




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Original post by z_o_e


Good, but for Q1 you can simplify that fraction and for Q5 you added the the denominators.
Use a Mathswatch CD , not sure if you're teachers can give you one for free (Worth a shot asking). They do step by step questions and answers and they make it seem easy.
Reply 1354
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Original post by RDKGames
Good, but for Q1 you can simplify that fraction and for Q5 you added the the denominators.


Oh yea :smile:

How do I do the others ?

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Original post by z_o_e
Oh yea :smile:

How do I do the others ?

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In the same way; make the denominators the same before adding them.
Reply 1356
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Original post by RDKGames
In the same way; make the denominators the same before adding them.


Yep did this


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Reply 1357
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Original post by z_o_e


Yep, you got the right idea. You can proceed to simplify.
Original post by z_o_e


ba+2a=2a2bba+2a=2a^2b ??? You're not multiplying them here.

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