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Mathematics C3 solution

Does anyone know how to solve this question?

Solve the equation, giving all values of x to the nearest degree in the interval 0<x<360: 2tan²x + secx - 1 = 0
Use 1+tan2x=sec2x 1+tan^2x=sec^2x
Original post by susans_crumpets
Does anyone know how to solve this question?

Solve the equation, giving all values of x to the nearest degree in the interval 0<x<360: 2tan²x + secx - 1 = 0


Use identity 1+tan2(x)=sec2(x)1+tan^2(x)=sec^2(x)
Use the identity sec⁡2≡tan⁡2+1\sec^2 \equiv \tan^2 +1 and see where that gets you
Use this identity
Well, nice to know at least three people have given the same advice eh?
Original post by dancepiratedance
Well, nice to know at least three people have given the same advice eh?


Reckon we need more people to say the same thing?
Original post by RDKGames
Reckon we need more people to say the same thing?

I think so, just to be absolutely sure
Use:

Cos2(x)Cos2(x)+Sin2(x)Cos2(x)=1Cos2(x) \frac{Cos^2 (x)}{Cos^2 (x)} + \frac{Sin^2 (x)}{Cos^2 (x)} = \frac{1}{Cos^2 (x)}

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