Write the balanced equation when calcium (10g) reacts with excess Hyrdrochloric acid to give a salt and hydrogen gas. a) Find the mass of hydrogen produced b) Find the volume of H2 produced. AR= H-1, Cl- 35.5, Ca-14 Molar Volume=24000cm
Please can someone show me how to do this (step by step)
First 2Ca + 2hcl = 2Cacl + h2 Get moles of Ca moles = mass / ar = 10/14 = 0.71 So now we assume Hcl has same moles 0.71 then convert cm3 volume to dm3 by 24000/1000 24dm3 So mass of h2 =moles x ar = 0.71 *1 = 0.71 Then v =molesx24 = 0.71*24 = 17.04g
First 2Ca + 2hcl = 2Cacl + h2 Get moles of Ca moles = mass / ar = 10/14 = 0.71 So now we assume Hcl has same moles 0.71 then convert cm3 volume to dm3 by 24000/1000 24dm3 So mass of h2 =moles x ar = 0.71 *1 = 0.71 Then v =molesx24 = 0.71*24 = 17.04g
I understand it, thank you! But why are you converting cm3 to dm3?
By the way do you have a source for the actual answers of this question please i request you notify me if the answers i got were correct or not if not then my apologies if yes Your welcome !🙆
I think the answers will be incorrect as the ar used is wrong in my opinion i referred to the periodic table there it has been stated as 40 so im really confused 😐😐
Write the balanced equation when calcium (10g) reacts with excess Hyrdrochloric acid to give a salt and hydrogen gas. a) Find the mass of hydrogen produced b) Find the volume of H2 produced. AR= H-1, Cl- 35.5, Ca-14 Molar Volume=24000cm
Please can someone show me how to do this (step by step)
I'm more interested on how the respondents to this thread have not picked out that the relative atomic of mass of Ca isn't 14! It's around 40
By the way do you have a source for the actual answers of this question please i request you notify me if the answers i got were correct or not if not then my apologies if yes Your welcome !🙆
First 2Ca + 2hcl = 2Cacl + h2 Get moles of Ca moles = mass / ar = 10/14 = 0.71 So now we assume Hcl has same moles 0.71 then convert cm3 volume to dm3 by 24000/1000 24dm3 So mass of h2 =moles x ar = 0.71 *1 = 0.71 Then v =molesx24 = 0.71*24 = 17.04g