Find the equation of the normal to y=cosecx at the point (1/2pi,1)
I differentiated this and got -coesecxcotx so if I want to find the gradient of the tangent, surely I just need to sub in 0.5pi in x. However it doesn't give me a value but it gives me 0 when I used the dy/dx button on my calculator... I think this is to do with the cotx graph not having a gradient at that point...
Thanks