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Kc

I worked out the Kc value as 8.69 mol dm-3 by doing 0.1725 x (0.345)^2 /0.1575 x 0.015
I'm not sure if this is right though. Could someone check please?
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Original post by osayukiigbinoba
I worked out the Kc value as 8.69 mol dm-3 by doing 0.1725 x (0.345)^2 /0.1575 x 0.015
I'm not sure if this is right though. Could someone check please?


I don't agree with your mole values at equilibrium.

Also don't forget that the equilibrium law needs to include the reaction coefficients as indexes of the mole concentrations (although volume is not needed as V cancels out in the calculation)
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yuki11
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Original post by charco
I don't agree with your mole values at equilibrium.

Also don't forget that the equilibrium law needs to include the reaction coefficients as indexes of the mole concentrations (although volume is not needed as V cancels out in the calculation)

Thank you, I've solved it now. My teacher helped me.

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