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differentiation

y=x^2/ax+b (a, b doesnt = 0)

show that d^2/dx^2 = 2b^2 /(ax+b)^3

i end up with 2a^2x^2 / (ax+b)^3

what have i done wrong??
Original post by Custardcream000
y=x^2/ax+b (a, b doesnt = 0)

show that d^2/dx^2 = 2b^2 /(ax+b)^3

i end up with 2a^2x^2 / (ax+b)^3

what have i done wrong??


Is that y=x2ax+by=\dfrac{x^2}{ax+b}?
What did you get for dydx\frac{\text{d}y}{\text{d}x}?
Original post by Kvothe the Arcane
Is that y=x2ax+by=\dfrac{x^2}{ax+b}?
What did you get for dydx\frac{\text{d}y}{\text{d}x}?


dy/dx = -ax^2(ax+b)^-2
Original post by Custardcream000
dy/dx = -ax^2(ax+b)^-2


That's incorrect. How did you get that?
Original post by Custardcream000
dy/dx = -ax^2(ax+b)^-2


i know what ive done wrong

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