Could somebody explain this Algebraic Operation?

Hi,

The question:

-[3x - (2y + 3) - 3x^2] = ?

The answer I have is 6xy + 9x - 3x^2. But, I suspect this is incorrect because I'm not entirely sure what the '[ ]' brackets mean in Maths. So, for instance, is the - (2y...' part equivalent to -2y?

Any help would be appreciated!

Thanks

first do this part "-(2y + 3)" = -2y - 3

then multiply each term by - 1 which is the "-[ ]" part

Thanks. Could you explain why -(2y + 3) becomes -2y - 3? And, why does '-[ ]' mean multiply each term by -1?

Thanks. Could you explain why -(2y + 3) becomes -2y - 3? And, why does '-[ ]' mean multiply each term by -1?

Thanks. Could you explain why -(2y + 3) becomes -2y - 3? And, why does '-[ ]' mean multiply each term by -1?

Hi,

The question:

-[3x - (2y + 3) - 3x^2] = ?

The answer I have is 6xy + 9x - 3x^2. But, I suspect this is incorrect because I'm not entirely sure what the '[ ]' brackets mean in Maths. So, for instance, is the - (2y...' part equivalent to -2y?

Any help would be appreciated!

Thanks

in this equation, the [ ] brackets basically say that the WHOLE equations is negative
so basically
-3x + (2y+3) + 3x²

check with someone else though, i might be wring

That makes sense - do I need to expand the bracket to reach the answer?

So does that mean the answer is -6xy - 9x + 3x^2? If not, why not?

It's not. Why not, you may ask?? Well that's hard to say when I don't know where you went wrong. For example, there is no $xy$ term so I don't know where you got that from in the first place. Just expand the normal brackets inside first, then the square bracket as a whole.

you need to multiply the terms in the round brackets by -1

-[3x-(2y+3)-3x^2] = -[3x(-2y-3)-3x^2]

The same way Reality Check got it in the post before yours