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Help with this question please :)

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Any help with question 4 would be much appreciated! How do you find the points of intersection?

Thanks

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I wish u could say this to maths:

@animeamanda1412 someone needs ur help:biggrin:
Reply 2
Original post by tamil fever
I wish u could say this to maths:

@animeamanda1412 someone needs ur help:biggrin:


lmaoo, i can never say that
im always gonna be like "maths, forever saty a cute little baby so i can always solve your questions"

and yh, what do you need help with?
Original post by JakeAntonyBrown
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Any help with question 4 would be much appreciated! How do you find the points of intersection?

Thanks


4a - solve for x (factorise) check it can be factorised with discriminant
4b - then put them into the equation of a straight line to find m or something like that
C1 :smile:
Original post by animeamanda1412
lmaoo, i can never say that
im always gonna be like "maths, forever saty a cute little baby so i can always solve your questions"

and yh, what do you need help with?


It's question 4, how do you find the points of intersection? :smile:

Thanks
Original post by tamil fever
I wish u could say this to maths:

@animeamanda1412 someone needs ur help:biggrin:



That's brilliant! I'd totally be saying that 90% of the time.
Original post by CheeseIsVeg
4a - solve for x (factorise) check it can be factorised with discriminant
4b - then put them into the equation of a straight line to find m or something like that
C1 :smile:


Thanks! For 4a, how would I solve for x?

:smile:
Original post by JakeAntonyBrown
Thanks! For 4a, how would I solve for x?

:smile:



you solve for by letting y=0
as x is common factor in all the three terms, you factorise it out and you will end up with a quadratic equation which I think you can factorise.
hope this helps
Original post by JakeAntonyBrown
Thanks! For 4a, how would I solve for x?

:smile:


You factorise.
Start by y=x^3-4x^2+3x
now what is common to all terms/what can you put outside the brackets?
Original post by JakeAntonyBrown
That's brilliant! I'd totally be saying that 90% of the time.

i say that 100% of the time.I've even written it in my tests:biggrin:
Original post by CheeseIsVeg
You factorise.
Start by y=x^3-4x^2+3x
now what is common to all terms/what can you put outside the brackets?


X is common in all?

:smile:
Original post by JakeAntonyBrown
X is common in all?

:smile:

yup so that gives:
y=x(x^2-4x+3)
Now this means one root x = 0 (when y= 0 ) Do you see how I got that?You have a quadratic to factorise now, I was hoping you could do that on your own to get the other two roots?
(x^2-4x+3)
Is this helping - I don't want to feed you answers without explanations if you see what I mean?
Original post by CheeseIsVeg
yup so that gives:
y=x(x^2-4x+3)
Now this means one root x = 0 (when y= 0 ) Do you see how I got that?You have a quadratic to factorise now, I was hoping you could do that on your own to get the other two roots?
(x^2-4x+3)
Is this helping - I don't want to feed you answers without explanations if you see what I mean?


I understand how we get to x(xˆ2-4x+3) but from there I'm lost.

Sorry :biggrin:
Original post by JakeAntonyBrown
I understand how we get to x(xˆ2-4x+3) but from there I'm lost.

Sorry :biggrin:


So y= x(xˆ2-4x+3) yep?Now if we seperate them into two parts, where the x intercepts are, y = 0
Therefore 0=x(xˆ2-4x+3)
Here you can find out that either x=0 (from the coefficient infront of the bracket)
or 0=(xˆ2-4x+3)

So you must factorise xˆ2-4x+3
Can you factorise or do you want to learn the Cheese way :rofl:
tbh, these questions are my weak points in maths
but i'll give a method im not sure you'd like
my teacher taught me a quick way, but i could never grasp it, so i always draw the curve, its better
so draw the curve on a piece of paper and from there you can get values of A, B and C
Original post by CheeseIsVeg
So y= x(xˆ2-4x+3) yep?Now if we seperate them into two parts, where the x intercepts are, y = 0
Therefore 0=x(xˆ2-4x+3)
Here you can find out that either x=0 (from the coefficient infront of the bracket)
or 0=(xˆ2-4x+3)

So you must factorise xˆ2-4x+3
Can you factorise or do you want to learn the Cheese way :rofl:


(x-3) (x-1)

I don't know where all my GCSE knowledge has gone, how did I manage to get an A* at GCSE and not know anything now?!? :P
Original post by JakeAntonyBrown
(x-3) (x-1)

I don't know where all my GCSE knowledge has gone, how did I manage to get an A* at GCSE and not know anything now?!? :P


yep you got it, so three roots are?
Are you good now? I've got to go and tackle C3 myself :tongue:
Good on you :yy: Just do a bit of revision, should be fine :wink:
Original post by CheeseIsVeg
yep you got it, so three roots are?
Are you good now? I've got to go and tackle C3 myself :tongue:
Good on you :yy: Just do a bit of revision, should be fine :wink:


+1
+3
and emmm???

Do you know what this topic would be called?

Thanks
Original post by JakeAntonyBrown
+1
+3
and emmm???

Do you know what this topic would be called?

Thanks

Factorising/solving a quadratic equation
and x=0 :wink:
Original post by CheeseIsVeg
Factorising/solving a quadratic equation
and x=0 :wink:


Thanks, how did you know x=0?

:smile:

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