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partial derivatives

Find the indicated partial derivative. u = e3rx sin x
3u/∂r2∂x=
(edited 7 years ago)
Reply 1
Original post by Rose86
Find the indicated partial derivative. u = e3rx sin x=
3u/∂r2∂x=


What seems to be the issue?
Whilst the computation is probably a little messy there are no real curve balls. . .
Reply 2
Original post by joostan
What seems to be the issue?
Whilst the computation is probably a little messy there are no real curve balls. . .


sorry???
Original post by Rose86
sorry???


Have you made a start on this? What have you got so far?
Reply 4
Differentiate twice with respect to r and then once with respect to x. It's the same process, three times.
Reply 5
Original post by mik1a
Differentiate twice with respect to r and then once with respect to x. It's the same process, three times.


Yes, I know. I know that. I did it but the answear is incorret😕
Reply 6
Original post by Rose86
Yes, I know. I know that. I did it but the answear is incorret😕


Sorry, I left my mind reader in the office.
Original post by Rose86
Yes, I know. I know that. I did it but the answear is incorret😕


If you post your working out we can look and see maybe where the error is.

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