The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Finding stationary points when derivative is in fraction form?

So i have derived the function 1/((x+5)(x-3)) using the reciprocal rule into 2x+2/((x+5)^2(x-3)^2) and am now very stuck on finding the stationary points from this.. any help would be much appreciated :wink:
Original post by adam9937999
So i have derived the function 1/((x+5)(x-3)) using the reciprocal rule into 2x+2/((x+5)^2(x-3)^2) and am now very stuck on finding the stationary points from this.. any help would be much appreciated :wink:


For a fixed non-zero constant or expression a, for what values of b is ab=0 \frac{a}{b} = 0?

Spoiler


So it doesn't matter what b is when the numerator is a non-zero constant or expression.. so when for what values of the numerator (a) will you find that dy/dx = 0?
(edited 7 years ago)
Reply 2
Avatar for adam9937999
adam9937999
OP
Original post by SeanFM
For a fixed non-zero constant a, for what values of b is ab=0 \frac{a}{b} = 0?

Spoiler


So it doesn't matter what b is when the numerator is a non-zero constant.. so when for what values of the numerator (a) will you find that dy/dx = 0?


Aaah yes! Thank you every so much fellow!
I've moved this into the maths forum as there are a lot more active mathematicians here, so hopefully you'll get better answers.
Original post by adam9937999
Aaah yes! Thank you every so much fellow!


No worries :h: so what did you get for your value of x?
Reply 5
Avatar for adam9937999
adam9937999
OP
Original post by SeanFM
No worries :h: so what did you get for your value of x?


-1! And that is the only stationary point as far as i am aware, so happy days.
Original post by adam9937999
-1! And that is the only stationary point as far as i am aware, so happy days.


Correct :h: well done. :borat:

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you