Stick x=2 and x=-2 in, try juggling that around?
2f(2) + 3f(-2) = 7
2f(-2) + 3f(2)= 23
then solve simultaneously
2f(2) + 3f(-2) = 7
2f(-2) + 3f(2)= 23
then solve simultaneously
(edited 7 years ago)
If you could also help me with this functions question please. Its a function inside a function which confuses me
Original post by an_atheist
Stick x=2 and x=-2 in, try juggling that around?
2f(2) + 3f(-2) = 7
2f(-2) + 3f(2)= 23
then solve simultaneously
2f(2) + 3f(-2) = 7
2f(-2) + 3f(2)= 23
then solve simultaneously
m=1 n=1, sub into the third function set to return f(0,f(1,0)). F(1,0) = f(0,1) = 2
F(0,2) = 3, B
That's the answer I get
F(0,2) = 3, B
That's the answer I get
Original post by an_atheist
m=1 n=1, sub into the third function set to return f(0,f(1,0)). F(1,0) = f(0,1) = 2
F(0,2) = 3, B
That's the answer I get
F(0,2) = 3, B
That's the answer I get
How do you solve the
f(0,f(1,0))
Original post by Carman3
How do you solve the
f(0,f(1,0))
f(0,f(1,0))
Firstly evaluate f(1,0)
Original post by RDKGames
Firstly evaluate f(1,0)
I got f(0,1) for that then what i do do i run it back through the function if so what line do i use
Original post by Carman3
I got f(0,1) for that then what i do do i run it back through the function if so what line do i use
Yeah so what is f(0,1)?? Check the conditions in the piecewise function to determine what happens.
It is easier to lay it out step by step:
(edited 7 years ago)
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