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Chemistry redox

20161110_115013.jpgCan someone go through a couple of these, and show me how to go about one?
(edited 7 years ago)

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Original post by Lucky10
20161110_115013.jpgCan someone go through a couple of these, and show me how to go about one?


Of course!
Let us start with SO2
Tell me what you know about the oxidation numbers of them already :smile:
Reply 2
Original post by CheeseIsVeg
Of course!
Let us start with SO2
Tell me what you know about the oxidation numbers of them already :smile:


S has a +2 charge and that oxygen has a -2 charge??
Original post by Lucky10
S has a +2 charge and that oxygen has a -2 charge??


Ok but remember with redox. If there are 2 non-metals, the most electronegative has te negative charge. Here this is oxygen, so it's oxidation number is -2.
This is a compound so that means the overall charge has to be 0.

So using this information. Sulphur must have a positive charge to counterbalance the 2 x (-2) (O2 = 2 times the -2 charge said above)
So Sulphur must be ...?
Reply 4
Original post by CheeseIsVeg
Ok but remember with redox. If there are 2 non-metals, the most electronegative has te negative charge. Here this is oxygen, so it's oxidation number is -2.
This is a compound so that means the overall charge has to be 0.

So using this information. Sulphur must have a positive charge to counterbalance the 2 x (-2) (O2 = 2 times the -2 charge said above)
So Sulphur must be ...?


+2??
Original post by Lucky10
+2??


No
So as oxygen has an oxidation number of -2
THere are 2 of them (-4)
ANd 1 sulphur
As the compound is neutral, it will have to balance out the -4 from the oxygen. so sulphur is +4

Try another?
Reply 6
Original post by CheeseIsVeg
No
So as oxygen has an oxidation number of -2
THere are 2 of them (-4)
ANd 1 sulphur
As the compound is neutral, it will have to balance out the -4 from the oxygen. so sulphur is +4
Oh right thats helped and yeah it that's okay with you
Try another?
oh right, thats helped and yeah if thats fine by you
Original post by Lucky10
oh right, thats helped and yeah if thats fine by you


Yay :hugs:
Do you mind posting one? on my phone and can't read the picture, sorry!
Reply 8
Original post by CheeseIsVeg
Yay :hugs:
Do you mind posting one? on my phone and can't read the picture, sorry!


NaH
Original post by Lucky10
NaH


NaOH or NaH?
Reply 10
Original post by CheeseIsVeg
NaOH or NaH?


NaH please
Original post by Lucky10
NaH please


Ok. So we know sodium is a group one metal. What do you know about the group one metals? :smile:
Grp 1 is 1+, Grp 2 is 2+, Grp 3 is 3+, Grp 6 is 2-, Grp 7 is 1-, And u gotta know maybe ur standard ions such as (So4)2-, (PO4)3-, (NO3)-. (CO3)2-
Reply 13
Original post by CheeseIsVeg
Ok. So we know sodium is a group one metal. What do you know about the group one metals? :smile:


That it has 1 electron in its outer most shell
Reply 14
Original post by OfficialChemist
Grp 1 is 1+, Grp 2 is 2+, Grp 3 is 3+, Grp 6 is 2-, Grp 7 is 1-, And u gotta know maybe ur standard ions such as (So4)2-, (PO4)3-, (NO3)-. (CO3)2-


yeahh
Reply 15
Original post by Lucky10
yeahh


Would it be -1 as sodium has a charge of +1
Original post by Lucky10
That it has 1 electron in its outer most shell

So it would form an ion of +1, hence its oxidation state :wink:
Original post by Lucky10
Would it be -1 as sodium has a charge of +1


H would be -1, yes
Remember the overall charge of this is 0 so you can see H must be -1 is Na is +1 :smile:
Reply 17
Original post by CheeseIsVeg
So it would form an ion of +1, hence its oxidation state :wink:


H would be -1, yes
Remember the overall charge of this is 0 so you can see H must be -1 is Na is +1 :smile:

Can we do one where its a minus
Reply 18
MnO42-
Original post by Lucky10
MnO42-


Yep so, sorry was eating food!
So we have an ion here.
So whatever happens, we need the sum of the oxidation states to have a charge of -2

We've spoken about Oxygen always being -2
So here we have 4 oxygens, each with -2
-2 times 4 = -8

Now hold on

We need an overall charge of -2
The only other species we have here is Mn
so its oxidation number must be ?

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