C1 Indices

I can't for toffee get around indices.

Can someone please explain how I'd turn y=10/x into an indice?

The question is "Find the equation of the normal to the curve y=10/x at the point (1,10)"

Reply 1

KaylaB

20

Original post by Elliwhi

I can't for toffee get around indices.

Can someone please explain how I'd turn y=10/x into an indice?

The question is "Find the equation of the normal to the curve y=10/x at the point (1,10)"

This question relies on knowing this rule about indices

If this is unfamiliar to you, I strongly recommend learning it.

But does this clear up how to turn

y = \frac{10} {x}

into an indice?

Reply 2

Desiboi101

2

10x^-1

Posted from TSR Mobile

Reply 3

KaylaB

20

Original post by Desiboi101

10x^-1

Posted from TSR Mobile

Congrats, you've just posted the answer and helped no one in the process :naughty:

Reply 4

username1628823

19

Index is the singular of indices. It's a mistake I make all the time, except I write indexes instead of indices.

I'd strongly recommend making a real effort to learn all of the rules for index notations ASAP, because they are essential in all of the core modules. You're setting yourself up to fail otherwise. Try this video:

[video="youtube;DX3ojeQmtH4"]https://www.youtube.com/watch?v=DX3ojeQmtH4[/video]

(edited 7 years ago)

Reply 5

Desiboi101

2

Original post by KaylaB

Congrats, you've just posted the answer and helped no one in the process :naughty:

Congrats, you're an ars*ehole

Posted from TSR Mobile

Reply 6

3121

21

Original post by Desiboi101

10x^-1

Posted from TSR Mobile

Big round of applause, it wasn't a competition… you could've at least explained that 1/x = x^-1 which needs to be multiplied by 10 giving 10/x on one side and 10x^-1 on the other hence the answer, it's about helping people learn not competing for an answer

Reply 7

username943595

OP

18

Original post by KaylaB

This question relies on knowing this rule about indices

If this is unfamiliar to you, I strongly recommend learning it.

But does this clear up how to turn <a rel="nofollow" href="javascript:void(0)"><img src="https://www.thestudentroom.co.uk/latexrender/pictures/76/76b68d871fbaded4917b60f275653e8b.png" width="53" height="24" style="border: 0px; margin: 0px; padding: 0px; vertical-align: -7px;" alt=" y = \frac{10} {x} " title=" y = \frac{10} {x} " onclick="newWindow=window.open('https://www.thestudentroom.co.uk/latexrender/latexcode.php?code=+y+%3D+%5Cfrac%7B10%7D+%7Bx%7D+','latexCode','toolbar=no,location=no,scrollbars=yes,resizable=yes,status=no,width=460,height=320,left=200,top=100');" /></a> into an indice?

Ah, this is the one pesky rule I keep forgetting. :/ Thank god for Christmas holidays and C1 revision :')

Original post by Jasaron

Index is the singular of indices. It's a mistake I make all the time, except I write indexes instead of indices.

I'd strongly recommend making a real effort to learn all of the rules for index notations ASAP, because they are essential in all of the core modules. You're setting yourself up to fail otherwise. Try this video:

[video="youtube;DX3ojeQmtH4"]https://www.youtube.com/watch?v=DX3ojeQmtH4[/video]

"Index is the singular of indices" I don't think any Maths teacher has ever told me that. Thanks for the video - I'll come back to it later once I've done this exercise aha))

Original post by zayn008

Big round of applause, it wasn't a competition… you could've at least explained that 1/x = x^-1 which needs to be multiplied by 10 giving 10/x on one side and 10x^-1 on the other hence the answer, it's about helping people learn not competing for an answer

GOD BLESS YOUR SOUL FOR THIS EXPLANATION: I GET IT NOW!!!!

Reply 8

Desiboi101

2

Original post by zayn008

Big round of applause, it wasn't a competition… you could've at least explained that 1/x = x^-1 which needs to be multiplied by 10 giving 10/x on one side and 10x^-1 on the other hence the answer, it's about helping people learn not competing for an answer