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Buffer Calculations

100 mL 0.1 M sodium acetate solution is mixed with 50 mL 0.1 M acetic acid. If now 0.914 mL of 1 M sodium hydroxide is added to the buffer what is the change in pH? pKa (acetic acid) = 4.76.
Original post by tasnzari09
100 mL 0.1 M sodium acetate solution is mixed with 50 mL 0.1 M acetic acid. If now 0.914 mL of 1 M sodium hydroxide is added to the buffer what is the change in pH? pKa (acetic acid) = 4.76.


You need to work out the pH before and the pH, subtract and that's the 'change in pH'.

Remember that its the pKa value, therefore you have to use the equation:

pH = pKa - log ([HA] / [A-])

Where HA is the acetic acid and A- is the OH- ion

@CheeseIsVeg this is right, right? :lol: :colondollar:
(edited 7 years ago)
Original post by titfortat
You need to work out the pH before and the pH, subtract and that's the 'change in pH'.

Remember that its the pKa value, therefore you have to use the equation:

pH = pKa - log ([HA] / [A-])

Where HA is the acetic acid and A- is the OH- ion

@CheeseIsVeg this is right, right? :lol: :colondollar:

Haven't done this yet so :dontknow:
Doing electrode potentials m9 :cool: :tongue:
Original post by CheeseIsVeg
Haven't done this yet so :dontknow:
Doing electrode potentials m9 :cool: :tongue:


Ahh well nvm then :rofl:

Thats the topic I hate the most in physical chem lmao XD
Original post by titfortat
Ahh well nvm then :rofl:

Thats the topic I hate the most in physical chem lmao XD


I love physical chem :fan: can't wait now lol

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