Edexcel IAL Physics Unit 1 - January 12, 2017

I do remember that it was something like that,

Good luck for the full UMS! Do youremember what you got for the frictional force the last part of that question!Was it around 17 or 18?i think i got it wrong.

Thank god I didn't exactly know what to do,i think i took the max value for delta x from the graph of the linear region and to find delta L or something and then put it all in the formula for Y.M

Was the points 90.06?
Was the angle of arrival of the skier 54?
What was the Youngs Modulus of the wire?
What was the mass of air in the first question?

Is the force of pull around 371 Newtons?

This year's exam was kinda weird. So many 4 mark questions for calculations. I tried the best as I could.

Thanks man you too. I saw that question in the last 2 minutes of my exam, I didn't see it before. I remember the resultant force being similar to 18 or something, lemme just go through what I did, I used F = ma and that's it. So 18 is really the resultant force, I shouldn't say it's the frictional force, the friction could've been found by 18 = Force of box on man - frictional force, but that's as far as I got. So I think if you got 18, you'll probably get 1 or 2 marks out of the 3 marks, I think.

But wasn't the question out of 4 marks? So what did u get as a frictional force on the PERSON? I got like 304.5N

could you inform me on how you did the first part of that question
i can kind of remember the question
the pull was 35 degrees to the horizontal and the mass of the box was 85 kilos
thats all

how could you get the magnitude of the force with only as much information
please help

Mass of box=85kg
Mass of person=90kg
Friction on the box (as calculated in b(ii))~305.5N
Acceleration of both mass and box=0.2ms-2
F=ma
F(box)=85*0.2
=17N
17N is resultant of pull (being the greatest) and friction
Therefore the total pull force is friction + resultant= 305.5+17N=325.5
But F(person)=90*0.2
= 18N
The considering that the pull force on the person is same 325.5 - 18 =304.5N

But didn't the question said that the man increased his pull on the object? If I remember correctly, I think it did which is why I didn't consider the pull force to be the same and left it at 18 N because I was confused m

Mass of box=85kg
Mass of person=90kg
Friction on the box (as calculated in b(ii))~305.5N
Acceleration of both mass and box=0.2ms-2
F=ma
F(box)=85*0.2
=17N
17N is resultant of pull (being the greatest) and friction
Therefore the total pull force is friction + resultant= 305.5+17N=325.5
But F(person)=90*0.2
= 18N
The considering that the pull force on the person is same 325.5 - 18 =304.5N