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C2 Help?!

in the expansion of (1+x/2)^n in ascending powers of x the coefficient of x^2 is 30.
a) find n
b) find the first four terms of the expansion

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Original post by ramshahk
in the expansion of (1+x/2)^n in ascending powers of x the coefficient of x^2 is 30.
a) find n
b) find the first four terms of the expansion


What is the coefficient of x^2 in terms of n in the expansion?
Reply 2
Original post by SeanFM
What is the coefficient of x^2 in terms of n in the expansion?


30
Original post by ramshahk
30


As I specified in my post - in terms of n?

Or, what are the first 3 terms in the expansion of (1+(x/2))^n?
Original post by ramshahk
in the expansion of (1+x/2)^n in ascending powers of x the coefficient of x^2 is 30.
a) find n
b) find the first four terms of the expansion


Can I encourage you to post A level maths questions in F38 (the Maths Forum)?

Could you use the formula in your formula book to write down the x2x^2 term in the expansion?
Reply 5
Original post by Mr M
Can I encourage you to post A level maths questions in F38 (the Maths Forum)?

Could you use the formula in your formula book to write down the x2x^2 term in the expansion?


i have tried but it doesnt work
Original post by ramshahk
i have tried but it doesnt work


Really? Can you post your working? A photo will do (assuming it is the right way up).
Reply 7
Original post by Mr M
Really? Can you post your working? A photo will do (assuming it is the right way up).


sorry i threw the working out in the bin ahaha
Reply 8
Original post by ramshahk
sorry i threw the working out in the bin ahaha


i dont know how to use the formula with this question
Original post by ramshahk
i dont know how to use the formula with this question


Ok I'll start you off.

(1+x2)n=1+n(x2)+n(n1)2!(x2)2+...(1+\frac{x}{2})^n = 1 + n(\frac{x}{2})+\frac{n(n-1)}{2!}(\frac{x}{2})^2 +...

You'll need to do some simplification and add a fourth term.
(edited 7 years ago)
Reply 10
Original post by Mr M
Ok I'll start you off.

(1+x2)n=1+n(x2)+n(n1)2!(x2)2+...(1+\frac{x}{2})^n = 1 + n(\frac{x}{2})+\frac{n(n-1)}{2!}(\frac{x}{2})^2 +...

You'll need to do some simplification and add a fourth term.


yeah what do you do after that
Original post by ramshahk
yeah what do you do after that


Use the fact that the coefficient of x2=30x^2=30. You'll need to form and solve a quadratic to find the value of nn.
Reply 12
Original post by Mr M
Use the fact that the coefficient of x2=30x^2=30. You'll need to form and solve a quadratic to find the value of nn.


??
Original post by ramshahk
??


I'm getting the impression this is too difficult for you at the moment. Could you ask your teacher to explain it to you tomorrow?
Reply 14
Original post by Mr M
I'm getting the impression this is too difficult for you at the moment. Could you ask your teacher to explain it to you tomorrow?


haha okay will do
@ramshahk Mr M has told you how to find the coefficient of x^2 algebraically (in terms of n).
You know that this is equal to 30 so can you form an equation with these two pieces of information in order to solve n?
(edited 7 years ago)
Reply 16
Original post by surina16
@ramshahk Mr M has told you how to find the coefficient of x^2 algebraically (in terms of n).
You know that this is equal to 30 so can you form an equation with these two pieces of information in order to solve n?


yeah i get that bit
Original post by ramshahk
yeah i get that bit


Great, so what did you get for n?
Reply 18
Original post by surina16
Great, so what did you get for n?


i didnt find out n
Original post by ramshahk
i didnt find out n


Mr M has given you the first few terms of the expansion. See that term with 3rd term (x2)2(\frac{x}{2})^2?? Rewrite it as Ax2A \cdot x^2 where A is a function of nn and make it equal to 30. Then solve for n.
(edited 7 years ago)

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