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Core 3 question

How do I solve this question please?

A curve has the equation y=e^2x(x^2-4x-2)
A) find the value of the x coordinate of each of the stationary points of the curve
Original post by Lucy373
How do I solve this question please?

A curve has the equation y=e^2x(x^2-4x-2)
A) find the value of the x coordinate of each of the stationary points of the curve


What is he first word that comes to mind when you see 'stationary points'?
Reply 2
Original post by SeanFM
What is he first word that comes to mind when you see 'stationary points'?

dy/dx=0
But not sure how to differentiate it?
Original post by Lucy373
dy/dx=0
But not sure how to differentiate it?


Since you have one function of x multiplied by another, you would use the .........? rule

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(edited 7 years ago)
Original post by Lucy373
dy/dx=0
But not sure how to differentiate it?


If you said f(x) = e^2x and g(x) = the quadratic... does that help? :smile:
Reply 5
Original post by SeanFM
If you said f(x) = e^2x and g(x) = the quadratic... does that help? :smile:

Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?
Original post by Lucy373
Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?


That is 50% of the answer. You have correctly found u'v but not uv' in the product rule of the form (uv)' = u'v + v'u if that is the notation you are used to.

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