c4 parametric help

Find and classify, the stationary points on the curves with parametric equations using first differential method. x=t^2 and y=t^3 -3t
dy/dx= 3t^2-3/2t

The stationary points are (1,2) when t =-1 and when t=1 the stationary point is (1,-2). The problem I'm having is when using first differential method I get that the points are inflection points, however this is wrong and they should be maximum and minimum points. Any help would be appreciated.
Thanks

Find and classify, the stationary points on the curves with parametric equations using first differential method. x=t^2 and y=t^3 -3t
dy/dx= 3t^2-3/2t

The stationary points are (1,2) when t =-1 and when t=1 the stationary point is (1,-2). The problem I'm having is when using first differential method I get that the points are inflection points, however this is wrong and they should be maximum and minimum points. Any help would be appreciated.
Thanks

Don't you mean second?

I tried second and I got the correct answer however the questions says use the first differential

I tried second and I got the correct answer however the questions says use the first differential

That works too, with t=.9 and t=1.1, then the negatives

is there a specific range when using first differential method? I tried 0.5 and 1.5

That works too, with t=.9 and t=1.1, then the negatives

When I put 0.9 I get a negative value and 1.1 get a positive value, wouldn't that be a point of inflection?

No, positve on both sides or negative on both sides would be a point of inflection. Positive on one side and negative on the other means it's a turning point, like the hump of a cubic