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Core 4 trigonometry

So .... what do I do from the last bit....

I have to solve the equation and I don't know what to do, have I been doing it right
(edited 7 years ago)
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Reply 1
Avatar for Notnek
Notnek
21
Original post by plower
So .... what do I do from the last bit....

I have to solve the equation and I don't know what to do, have I been doing it right

Third line has a mistake on the numerator. You shouldn't be multiplying by the −3-3. Have another look at it.

Also I recommend using cos⁡2x=1−2sin⁡2x\cos 2x = 1-2\sin^2 x instead. Then your equation will only have sines at an earlier stage of the working.
Reply 2
Avatar for plower
plower
OP
9
Original post by notnek
Third line has a mistake on the numerator. You shouldn't be multiplying by the −3-3. Have another look at it.

Also I recommend using cos⁡2x=1−2sin⁡2x\cos 2x = 1-2\sin^2 x instead. Then your equation will only have sines at an earlier stage of the working.


Ohhhhhhhh silly me, tysm!

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