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c2 help

....
(edited 6 years ago)
Original post by years101
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for 4)

i wrote down
2x + 8x^-2

dy/dx = 2 + -16x^-3

made it equal to 0

do I factorise now?Well, you don't need to factorize, but you do need to find where 2-16/x^3 = 0.
Original post by years101


You can factorise but there is no reason to realistically. Just set dy/dx=0 for the stationary point and find its coordinates, then determine its nature via second derivative.
ok....so you take the equation given in the question and you rearrange it so it becomes y= 2x + 8x^-2
Then you differentiate it to dy/dx = -16x + 2
Now you can equate it to zero and work out the value of x, i.e 1/8 or 0.125
Then you have to make a table.

Hth :h:
Original post by Batgirl98
...
Then you have to make a table.


Incorrect derivative, but table for what...?
(edited 7 years ago)
if you enjoy factorising then go ahead :h:

x3 - 8 = ( x - a ) ( x2 + bx + c )

where a,b,c are integers.

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