Whilst I am here, to save me from making a new thread...
When calculating the time using s = ut + 0.5at^2, do you have to show that the solution can be either positive or negative, and then state that the time can not take a negative value?
When calculating the time using s = ut + 0.5at^2, do you have to show that the solution can be either positive or negative, and then state that the time can not take a negative value?
I would state that, 'for t>=0 the solution is', but I don't know how this gets marked.
A car moves along a straight road. When it passes a set of traffic lights the car is travelling at a speed of 8ms-1 the car then moves with a constant acceleration for 10 seconds and travels 200metres. A) show that the acceleration is 2.4ms-2 B) find the speed of the car at the end of the 10 seconds C) the road is horizontal and the car has mass 1200kg. A constant resistance force of 1800n acts on the car while it is moving. (I) find the magnitude of the driving force that acts on the car while it is moving (Ii) at the end of the 10 second period the driving force is removed the car then moves subject to the resistance force of 1800n until it stops . Find the distance that the car travels while it is slowing down Can some help with c)ii please
C) the road is horizontal and the car has mass 1200kg. A constant resistance force of 1800n acts on the car while it is moving. (I) find the magnitude of the driving force that acts on the car while it is moving (Ii) at the end of the 10 second period the driving force is removed the car then moves subject to the resistance force of 1800n until it stops . Find the distance that the car travels while it is slowing down Can some help with c)ii please
You have the initial speed from B, and the (constant) acceleration (negative) from F=ma. What formulas are you expected to have? (If needed, you can easily calculate the time taken to stop)
You have the initial speed from B, and the (constant) acceleration (negative) from F=ma. What formulas are you expected to have? (If needed, you can easily calculate the time taken to stop)
it is in the Newton's second law section so f=am I think
You have the initial speed (u), end speed (v=0) and the deceleration. You should be able to use the formula above to calculate the distance traveled (s).
You have the initial speed (u), end speed (v=0) and the deceleration. You should be able to use the formula above to calculate the distance traveled (s).