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Zoes GCSE maths help

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Reply 20
Original post by RDKGames
Work out the area of the cross section first before multiplying it by 20 which is the depth of the prism.



Any help on understanding this question please


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Original post by z_o_e
Any help on understanding this question please


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25 litres is made up from orange juice, lemonade, and cranberry juice.

To work out the amount of orange juice, work out 50% of 25 litres. To work out the amount of lemonade, work out 25\frac{2}{5} of 25 litres, etc...
Reply 22
Original post by RDKGames
25 litres is made up from orange juice, lemonade, and cranberry juice.

To work out the amount of orange juice, work out 50% of 25 litres. To work out the amount of lemonade, work out 25\frac{2}{5} of 25 litres, etc...


Thank you so much!!

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Reply 23
Can someone help me on this please

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Reply 24
Original post by z_o_e
Can someone help me on this please

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It's a 600ml bottle of remover and you mix a 1/4 of it with 4500ml water.

So that means you mix 150ml remover with 4500ml water.

So the ratio of remover to water must be 150:4500. Can you simplify this ratio?
Reply 25
Original post by notnek
It's a 600ml bottle of remover and you mix a 1/4 of it with 4500ml water.

So that means you mix 150ml remover with 4500ml water.

So the ratio of remover to water must be 150:4500. Can you simplify this ratio?

30ml

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Reply 26
Help on this would be appropriated

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Reply 27

The ratio is 1:30 yes.

So if you use 750ml of water, how much remover do you need?
Reply 28
Original post by z_o_e
Help on this would be appropriated

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Are those your lines on the diagram? They're correct and the lines on the left of the dot should be 1.5 times the length of the lines on the right of the dot.

If you're unsure please explain why.
Reply 29
Original post by notnek
The ratio is 1:30 yes.

So if you use 750ml of water, how much remover do you need?


25

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Reply 30

That's correct.
Reply 31
Original post by notnek
Are those your lines on the diagram? They're correct and the lines on the left of the dot should be 1.5 times the length of the lines on the right of the dot.

If you're unsure please explain why.


I'm still stuck on the scale factor one. I don't know where to start from

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Reply 32
Original post by z_o_e
I'm still stuck on the scale factor one. I don't know where to start from

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Are those not your lines on the diagram? You start from the centre of enlargement which is the point drawn on your diagram.
Reply 33
Original post by notnek
Are those not your lines on the diagram? You start from the centre of enlargement which is the point drawn on your diagram.


Yep and then count each square up till the centre and times it by -0.5

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Reply 34
Can someone help me on this please


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Reply 35
Original post by z_o_e
Can someone help me on this please


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You're finding the lowest common multiple of 5, 8 and 12 and then seeing how many packets you need of each candle so that you have the lowest common multiple number of each candle.
Can you find the LCM?
Reply 36
Original post by B_9710
You're finding the lowest common multiple of 5, 8 and 12 and then seeing how many packets you need of each candle so that you have the lowest common multiple number of each candle.
Can you find the LCM?


Heya can you help me on this please

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Reply 37
Original post by z_o_e
Heya can you help me on this please

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You need to write each surd in terms of 2\sqrt{2}.

So for 8\sqrt{8}, you can write this as 4×2\sqrt{4 \times 2}

And if you split up the root you get this

4×2=4×2=22\sqrt{4\times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}

Have a go at the rest of the surds and please post your working if you get stuck.
Reply 38
Original post by notnek
You need to write each surd in terms of 2\sqrt{2}.

So for 8\sqrt{8}, you can write this as 4×2\sqrt{4 \times 2}

And if you split up the root you get this

4×2=4×2=22\sqrt{4\times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}

Have a go at the rest of the surds and please post your working if you get stuck.


I've done this so far

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Reply 39
Original post by z_o_e
I've done this so far

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Now you just need to combine all the like terms. You can deal with surds similar to how you deal with letters in algebra so what's this:

7x+6x10x7x+6x-10x

?

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