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GCSE Maths Help and Chat Thread

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Reply 120
Avatar for Zxrxh
Zxrxh
3
Original post by _gcx
No, can you post your working?


is the answer 39.05

100/10 = 10
10 x 58.5 = 585

100/11=9.09
9.09 x 60= 545.45

585 - 545.45 = 39.05

is that right ??
Reply 121
Avatar for Vvlpes
Vvlpes
1
Help?
mathswatchcirclehthereoms.png
Original post by Zxrxh
is the answer 39.05

100/10 = 10
10 x 58.5 = 585

100/11=9.09
9.09 x 60= 545.45

585 - 545.45 = 39.05

is that right ??


His test score should be a whole number.

His total mark after 9 tests is 531 (9∗59=5319*59=531). His total mark after 10 tests is 585. (10∗58.510*58.5) What did he get in the 10th test?

You can use a similar process to work out what achieved in the 11th test.
Reply 123
Avatar for Zxrxh
Zxrxh
3
Original post by _gcx
His test score should be a whole number.

His total mark after 9 tests is 531 (9∗59=5319*59=531). His total mark after 10 tests is 585. (10∗58.510*58.5) What did he get in the 10th test?

You can use a similar process to work out what achieved in the 11th test.

60 x 11 = 660
Reply 124
Avatar for Zxrxh
Zxrxh
3
Original post by _gcx
His test score should be a whole number.

His total mark after 9 tests is 531 (9∗59=5319*59=531). His total mark after 10 tests is 585. (10∗58.510*58.5) What did he get in the 10th test?

You can use a similar process to work out what achieved in the 11th test.


is the answer 75 ?
Original post by Vvlpes
Help?

Hint : cyclic quadrilaterals.
Reply 126
Avatar for Vvlpes
Vvlpes
1
Original post by notnek
Hint : cyclic quadrilaterals.


Is APDO a cyclic quadrilateral? I though all corners have to be touching the circumference?
Original post by Vvlpes
Is APDO a cyclic quadrilateral? I though all corners have to be touching the circumference?

No but APDB is.
Reply 128
Avatar for Vvlpes
Vvlpes
1
Original post by notnek
No but APDB is.


Holy smokes! it was right in front of my the whole time!
Original post by Zxrxh
is the answer 75 ?


He received 75 for his 11th test. However, the question is asking for the difference between the 11th and 10th test, so subtract his 10th mark from 75, to get your answer.
Reply 130
Avatar for Zxrxh
Zxrxh
3
Original post by _gcx
He received 75 for his 11th test. However, the question is asking for the difference between the 11th and 10th test, so subtract his 10th mark from 75, to get your answer.


how did you get 75 for his 11 th test?
Original post by Zxrxh
how did you get 75 for his 11 th test?


We know that the sum of his scores after the 10th was 585, as you have worked out. The sum after the 11th test was 660 (60∗1160*11). Therefore, we know that he received a mark of 75 in his 11th test.

Note that the mean mark is the sum of his marks, divided by the amount of tests that he has taken.
Reply 132
Avatar for Zxrxh
Zxrxh
3
Can you help me with this question please :smile:

At a birthday party, there is a 750g chocolate cake and a 600g carrot cake.

At the party, 50% of the total weight of cake was eaten.

Given that 54% of the chocolate cake was eaten, work out the percentage of the carrot cake that was eaten. (3 marks)
Original post by Zxrxh
Can you help me with this question please :smile:

At a birthday party, there is a 750g chocolate cake and a 600g carrot cake.

At the party, 50% of the total weight of cake was eaten.

Given that 54% of the chocolate cake was eaten, work out the percentage of the carrot cake that was eaten. (3 marks)

So there is 750 + 600 = 1350g total weight of cake and 50% of cake is eaten so that means 1350 ÷2 = 675g of cake was eaten.

The next step is to work out how much chocolate cake was eaten (you are told that 54% of chocolate cake is eaten). Can you continue from here?
Reply 134
Avatar for Zxrxh
Zxrxh
3
Original post by notnek
So there is 750 + 600 = 1350g total weight of cake and 50% of cake is eaten so that means 1350 ÷2 = 675g of cake was eaten.

The next step is to work out how much chocolate cake was eaten (you are told that 54% of chocolate cake is eaten). Can you continue from here?


do you just do 54% of 675 and then take away that answer by 675g ?
ccy
Original post by Zxrxh
do you just do 54% of 675 and then take away that answer by 675g ?

No 675g is the total amount of cake (of both types) that was eaten.

54% of the chocolate cake was eaten which means that 54% of 750g of chocolate cake was eaten.
Reply 137
Avatar for Zxrxh
Zxrxh
3
Original post by notnek
No 675g is the total amount of cake (of both types) that was eaten.

54% of the chocolate cake was eaten which means that 54% of 750g of chocolate cake was eaten.


im gonna fail maths :frown:
Hey can anyone check to see if my answer of 8.2 to 1.dp is correct please?
Maths-16-2015.pdf - Google Chrome 16_03_2017 20_59_03.png
Original post by CraigBackner
Hey can anyone check to see if my answer of 8.2 to 1.dp is correct please?
Maths-16-2015.pdf - Google Chrome 16_03_2017 20_59_03.png

Yes that's correct.

It's useful for questions with diagrams to check if your answer makes sense (although be careful since diagrams aren't always drawn to scale) : AB looks like it's a similar length to EF so the answer 8.2 looks fine.

If for example you got something like 20cm for EF then this would seem a bit odd so it would be worth double checking your working to see if you made a mistake.

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