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Chemistry help!!

Can anyone help me with these??

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Reply 1
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Original post by Lucky10
Can anyone help me with these??


? :smile:
m= mass of solution, equal to total volume (e.g in first one its 50)
c= specific heat capacity, 4.18 for water
delta T= change in temp- t2-t1

delta h, enthalpy of solution-= Q/n where n is number of moles, found in normal mass/mr way
Reply 4
Original post by Hajra Momoniat
? :smile:


Ive posted it now
Reply 5
which q?
Reply 6
Original post by glad-he-ate-her
m= mass of solution, equal to total volume (e.g in first one its 50)
c= specific heat capacity, 4.18 for water
delta T= change in temp- t2-t1

delta h, enthalpy of solution-= Q/n where n is number of moles, found in normal mass/mr way


Could you show me an example with the first one please
q=mc delta t
m=25+25= 50g as 1g is approx 1 cm cubed
c=4.18
delta t= 12
q=50*4.18*12=2508J

can you find the moles and use that to find delta h? using delta h= q/n
you can also use the equation n= conc* vol to find moles
Reply 8
The question itself
Original post by 06moca1
which q?
Reply 9
Original post by glad-he-ate-her
q=mc delta t
m=25+25= 50g as 1g is approx 1 cm cubed
c=4.18
delta t= 12
q=50*4.18*12=2508J

can you find the moles and use that to find delta h? using delta h= q/n
you can also use the equation n= conc* vol to find moles


I'm not sure
Original post by Lucky10
I'm not sure


n=2.00*25/1000=0.05
can you finish?
Reply 11
Original post by glad-he-ate-her
n=2.00*25/1000=0.05
can you finish?
is the change -1.254?
Original post by Lucky10
is the change -1.254?


Not quite, we have q= 2508 and n=0.05 and delta h=q/n
Reply 13
Original post by glad-he-ate-her
Not quite, we have q= 2508 and n=0.05 and delta h=q/n


Don't we need to divide it by 1000? Also isnt change in minus?
Original post by Lucky10
Don't we need to divide it by 1000? Also isnt change in minus?


Divide the Delta h by 1000- you can but its easier to do at end of calculation- delta h=-q/n but its easier to use q/ n and convert at the end depending on whether the reaction is exothermic or endothermic- this one is exo so it is negative so answer is 2508/0.05=50160j/mol, you can divide by 1000 to get 50.16kj/mol and put a negative as its exo for final answer of -50.16kj/mol
Reply 15
Original post by glad-he-ate-her
Divide the Delta h by 1000- you can but its easier to do at end of calculation- delta h=-q/n but its easier to use q/ n and convert at the end depending on whether the reaction is exothermic or endothermic- this one is exo so it is negative so answer is 2508/0.05=50160j/mol, you can divide by 1000 to get 50.16kj/mol and put a negative as its exo for final answer of -50.16kj/mol


I thought like you divide the 2508j by 1000? Or is it already converted? So how do you if it's exo or endo and so question will be 100x4.18x18.8??
Original post by Lucky10
I thought like you divide the 2508j by 1000? Or is it already converted? So how do you if it's exo or endo and so question will be 100x4.18x18.8??


you can divide it by 1000- do that if youre comfortable- i suggested doing that at the end but whatever youre used to and im looking at q1 where the temp change is 12 and mass=50, exo and endo is deduced from whether temp has risen or fallen- if surroundings risen, exothermic - if surrounding temp fallen, endothermic
Reply 17
Original post by glad-he-ate-her
you can divide it by 1000- do that if youre comfortable- i suggested doing that at the end but whatever youre used to and im looking at q1 where the temp change is 12 and mass=50, exo and endo is deduced from whether temp has risen or fallen- if surroundings risen, exothermic - if surrounding temp fallen, endothermic


So would q2 be 100x4.18 x 18.8?
Original post by Lucky10
So would q2 be 100x4.18 x 18.8?


no, total mass = 100+100=200
Delta t= 6.8
q= 200*4.18*6.8
Reply 19
Original post by glad-he-ate-her
no, total mass = 100+100=200
Delta t= 6.8
q= 200*4.18*6.8


Alright I got you can you help me on 4c that's it

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