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Edexcel IAL Physics Unit 03 WPH03 - 10th of May, 2017

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Original post by theeconomistkid
I got 2*10^10 and volume of the liquid.. because no matter how much volume you have it doesn't affect how sticky your caramel is gonna be right? :wink:


Haha true that but for the gradient did u get 714.28 the gradient not young modulous
Reply 41
Exam was overall good. I am expecting there to be a high grade boundary.
Original post by Hola1234
Haha true that but for the gradient did u get 714.28 the gradient not young modulous


YES GURL I GOT IT!!!!!! I JUST RE USED THE VALUES FROM THE TABLE LOL AND USED (0,0) as well
Original post by theeconomistkid
YES GURL I GOT IT!!!!!! I JUST RE USED THE VALUES FROM THE TABLE LOL AND USED (0,0) as well


Ok but what was ur actual value for gradient
what values for force and extension did u guys use to get 2*10^10?
what was ans for percentage uncertainty?


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Reply 46
Original post by ree.x09
what was ans for percentage uncertainty?


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I got 6%
Reply 47
Original post by Ultnari
I got 6%


Percentage uncertainty was 1.7%
Original post by AdemN
Percentage uncertainty was 1.7%


Yeh even I got that
Reply 49
How did you calculate the percentage uncertainty
Reply 50
Original post by AdemN
Percentage uncertainty was 1.7%


For the percentage uncertainty weren't we supposed to change 0.01mm into cm then divide it by 6 and multiply it by 100?
Original post by zenab_k
For the 6cm was it like the burns occur at nodes therefore one wavelength is distance btw 2 nodes

It's two antinodes!
Original post by zenab_k
For the percentage uncertainty weren't we supposed to change 0.01mm into cm then divide it by 6 and multiply it by 100?


The uncertainty was +/- 1mm
Therefore the percenage uncertainty is 1/60 *100 which gives 1.7%
Original post by mandax_25
The uncertainty was +/- 1mm
Therefore the percenage uncertainty is 1/60 *100 which gives 1.7%


Uncertainty on metre rule is +/- 0.5mm, 0.5/60 = 0.83%
Reply 54
Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )
Original post by Luj99
Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )


Did you remember to convert everything to metres?
Would I get mark for including unit (Nm^-2) in last question but no answer
Reply 57
Original post by theeconomistkid
Did you remember to convert everything to metres?
I think I did and how did your force against extension graph look like ?
Reply 58
Original post by Chapers64
Would I get mark for including unit (Nm^-2) in last question but no answer


I think they give marks for the units and formula
Reply 59
was it supposed to be 1.91 x 10^10 ???
Original post by Luj99
Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )
(edited 6 years ago)

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