The Student Room Group

Edexcel Maths FP1 UNOFFICIAL Mark Scheme 19th May 2017

Scroll to see replies

What was the mark breakdown for each question?
someone post the actual paper pls
Original post by Redcoats
exact same as what i got


yeah thats the same as me :smile:
for the matrices question how many marks do i lose if i only got 9/2 ???
Original post by Prodanski
do you think its going to be ignore further working, or will i lose marks?


Some mark schemes will penalise, some will ignore, im not sure here
Original post by X_IDE_sidf
This is how I did it, but the comment was made that the geometric series formula in C2 would have been more elegant ( https://www.varsitytutors.com/hotmath/hotmath_help/topics/geometric-series )


Ok sorry for the delay, I haven't done geometric series since last year.
So the formula is a(r^n-1)/r-1
a being the first number and r being the common ratio
so 1(2^12)/2-1 =4095 therefore
4095k = 910
the key thing here is that n =12, not 11
Could someone please explain why for 4b p=20?? If arg(w)=0.25pi, doesn't that mean 2p+12=3p+8?
Original post by DystopiaisReal
Could someone please explain why for 4b p=20?? If arg(w)=0.25pi, doesn't that mean 2p+12=3p+8?


Yeah but I think it was 3p -8 = 2p + 12
Reply 128
Avatar for Vzheng
Vzheng
When will the paper be released?
Does anyone know how many marks question 7 was?
Original post by glad-he-ate-her
Am i the only one who forgot the sum for 2 to the power of r-1 from c2 so manually wrote out all 12 terms :clap2:such mathematical elegance


yeah i the same thing hopefully its allowed
Original post by DystopiaisReal
Could someone please explain why for 4b p=20?? If arg(w)=0.25pi, doesn't that mean 2p+12=3p+8?


I'm sorry I made the classic slip of the pen. you muddled up the sign. It is 2p+12=3p-8

Thanks for noticing
Reply 132
Avatar for Hasad
Hasad
7
Original post by 04MR17
Question 3 - Coordinate systems (hyperbola)

a.) y=(1/2)x [3]
b.) xy=16 [1]
c.) (4sqrt(2), 2sqrt(2)) and (-4sqrt(2),-2sqrt(2)) [3]


Ahh i got confused and put xy = 4, would i lose the 4 marks?
Original post by TrueDAN
Yeah but I think it was 3p -8 = 2p + 12


Okay that makes me feel marginally more secure; but I still did terribly overall
For the divisible by 19 proof question I brought the 3^-2 down and multiplied f(k) by 27 then minused it from f(k+1) to eliminate the 3^k.I was able to prove it was divisible by 19 so would I still get full marks even if it's not the main method
Original post by DystopiaisReal
Okay that makes me feel marginally more secure; but I still did terribly overall


Don't worry about it - it was my worst exam first year hence I am resitting it. You've probably not done as bad as you thought!!
Original post by Aceofall
I tHought we were meant to find k+2 or am I wrong?


Yes I think both ways are acceptable, it looks like most people have proved it your way though. It'll be interesting to see what the mark scheme says.
Original post by 04MR17
Question 6: Complex Numbers
a.) -3-2i [1]
b.) a=2, b=-11 [5]

Question 7: Coordinate systems
a.) Show that
b.) D: (-a , -3/2 a)
c.) (15a2)/16


do you know how many marks each part of q7 is?
Original post by glad-he-ate-her
Am i the only one who forgot the sum for 2 to the power of r-1 from c2 so manually wrote out all 12 terms :clap2:such mathematical elegance


lmao I did the exact same thing lool. How do you do it normally?
Original post by glad-he-ate-her
Am i the only one who forgot the sum for 2 to the power of r-1 from c2 so manually wrote out all 12 terms :clap2:such mathematical elegance


You are not the only one lol :smile: I knew at the time it was C2 related but I just didn't know how to do it that way - so wrote all 12 terms in terms of k, added them up and got it right too!

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you