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Mr M's OCR (not OCR MEI) Core 2 Answers May 2017

Mr M's OCR (not OCR MEI) Core 2 Answers May 2017


1. (i) 4 (4 marks)

(ii) 636 \sqrt 3 (2 marks)


2. (i) 0.715 (4 marks)

(ii) Underestimate because trapeziums lie under the curve (2 marks)


3. (i) 1+4x+7x2+7x31+4x+7x^2+7x^3 (4 marks)

(ii) 11 (2 marks)


4. y=2x525x2+27y=2x^{\frac{5}{2}}-5x^2+27 (6 marks)


5. 2.19 (6 marks)


6. 116\frac{11}{6} (7 marks)


7. a) 314 (4 marks)

b) i) Show y=2x21y=2x^2-1 (4 marks)

ii) x=2 and y=7 or x=3 and y=17 (4 marks)


8. a) a=24a=-24 (5 marks)

b) a=30142a=30-14\sqrt2 (6 marks)


9. (i) Show and f(x)=(2x1)(2x2+x+5)f(x)=(2x-1)(2x^2+x+5) (4 marks)

ii) a) Show (4 marks)

b) θ=π12\theta=\frac{\pi}{12} and θ=5π12\theta = \frac{5\pi}{12} and θ=13π12\theta=\frac{13\pi}{12} and θ=17π12\theta=\frac{17\pi}{12}(4 marks)


Heck. 9 was wrong. Now fixed.
(edited 6 years ago)

Scroll to see replies

I do believe that there should be 4 answers to the final question, because it was actually sin(2*theta) rather than sin(theta)

**EDIT** - This has now been fixed
(edited 6 years ago)
What was question 5? (Not the answer. The question)
Original post by temmerson
I do believe that there should be 4 answers to the final question, because it was actually sin(2*theta) rather than sin(theta)


You are incorrect, it was 100% 0.5sin(√theta) not sin(2*theta)
Reply 4
The answer to the last Q is wrong there is 4 solutions
Original post by Saaam1234
What was question 5? (Not the answer. The question)


Rhombus question?
Reply 6
Are there not 4 solutions for last part of last question? As 2x divides by two so answers also fit in range 0<x< 2pi to get 390 degrees and 520 degrees which when divided by 2 also fit in range (change to radians)...
Original post by Saaam1234
What was question 5? (Not the answer. The question)


Sector AOB arc length 6 cm and sector area 24 cm^2. Find area of shaded segment to 3 sf.
Reply 8
I did the trapezium rule equation is degrees so I got the wrong answer.
Also I got x=-2 and x=-3 for 7bii) still got the right y co-ordinates.

How many marks would I lose for these mistakes thanks!
Reply 9
Mr M these solutions are missing 13/12 pi and 17/12 pi
(edited 6 years ago)
What was 3(i) and (ii)?
Reply 11
Dear Mr. M, are you sure there's only 2 answers for the final part?
Original post by temmerson
I do believe that there should be 4 answers to the final question, because it was actually sin(2*theta) rather than sin(theta)


Sorry. Now fixed.
Reply 13
I got x=3 on q1 because I -4 instead of adding it...how many marks would I lose for both part one and two?
Reply 14
Dear Mr. M, how many marks would I lose for getting the four correct answers at the end but eliminating two of them so I only gave two angles for my final answer?
Original post by AaronC88
I did the trapezium rule equation is degrees so I got the wrong answer.
Also I got x=-2 and x=-3 for 7bii) still got the right y co-ordinates.

How many marks would I lose for these mistakes thanks!


Lose one for degrees.

Lose one for failing to solve quadratic properly.
Original post by Hazzer65
Rhombus question?


Eh?
what was the question 6i, 7bii and 8b??
I only put the first 2 solutions for q9, how many marks lost???
Original post by phat-chewbacca
What was 3(i) and (ii)?


First 4 terms of (1+x2)8(1+\frac{x}{2})^8

Coeff of y2y^2 of (1+12(y+y2))8(1+\frac{1}{2}(y+y^2))^8

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