M proportional to pressure and L is proportional to volume therefore graph is a straight line through the original.
I thought L cant be 0 cause other PV=nrt doesnt apply because they'd be no volume so I put mine positive constant gradient starting further down the x axis?
I thought L cant be 0 cause other PV=nrt doesnt apply because they'd be no volume so I put mine positive constant gradient starting further down the x axis?
Ahh yeah that sounds better, I honestly was just thrown by the exam so i panicked on every question pretty much
dunno exactly what the questions are in order, or the numbers, but can remember the method probably
1) strontium and alpha nucleus a) velocity of alpha nucleus energy and mass given therefore 1/2*m*v^2 b) newtons laws to explain motion of strontium strontium experiences a force as alpha particle experiences a change in momentum? Repulsion between the two are equal and opposite, also act on each others bodies? c) calculate v of strontium M(initial)*v(initial) = M(final)^v(final)
2) ?
3)
4)
5)Thermal physics a) work out initial n of baloon use 4/3*pi*r^3 and PV=nRT using initial T, P b) work out final pressure of baloon before it pops use 4/3*pi*r^3 for new V and PV=nRT using final T, initial n, final V c) ratio question E=3/2KT therefore ratio is T(final)/T(initial)
Help.. pls
I'll see how much I can recall. Unfortunately, I can't quite remember all the numbers, feel free to chime in if anyone else does.
2) SHM - Straight line through the origin suggests SHM - Why the mass attached to spring went towards the outside when rotated - State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived]) - Calculate units for k =kg s^-2 - Calculate k/m (i.e. the gradient.) (they gave units of s^-2, confirming previous answer.) - How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.) - Experiment for R, F and v using video camera and ruler.
3) Gravity Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km - Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.) - Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.) - 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.) - Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg]) - The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta). 45mA of 130keV electrons for 1.6s. - Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x10-3)(1.6)/(1.6x10-19)=4.5x10^17 electrons) - Calculate wavelength. (E=130keV=2.08x10-14J. E=hc/wavelength->wavelength=9.56x10-12 m) Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^-3[?] - Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x10-14)=9360 J. E=mc(theta)->m=E/c(theta)=(9360)/(4200)(27-17)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs-1. volume per second=(0.139)/1000= 1.39x10-4 m^3 s^-1 [Not entirely sure about this one due to forgetting the density.]
I'll see how much I can recall. Unfortunately, I can't quite remember all the numbers, feel free to chime in if anyone else does.
2) SHM - Straight line through the origin suggests SHM - Why the mass attached to spring went towards the outside when rotated - State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived]) - Calculate units for k =kg s^-2 - Calculate k/m (i.e. the gradient.) (they gave units of s^-2, confirming previous answer.) - How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.) - Experiment for R, F and v using video camera and ruler.
3) Gravity Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km - Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.) - Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.) - 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.) - Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg]) - The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta). 45mA of 130keV electrons for 1.6s. - Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x10-3)(1.6)/(1.6x10-19)=4.5x10^17 electrons) - Calculate wavelength. (E=130keV=2.08x10-14J. E=hc/wavelength->wavelength=9.56x10-12 m) Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^-3[?] - Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x10-14)=9360 J. E=mc(theta)->m=E/c(theta)=(9360)/(4200)(27-17)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs-1. volume per second=(0.139)/1000= 1.39x10-4 m^3 s^-1 [Not entirely sure about this one due to forgetting the density.]
Slightly worried as I don't have any recollection of your Q3!
Slightly worried as I don't have any recollection of your Q3!
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
Same, that's what I did, I even put a little note lol.
I'll see how much I can recall. Unfortunately, I can't quite remember all the numbers, feel free to chime in if anyone else does.
2) SHM - Straight line through the origin suggests SHM - Why the mass attached to spring went towards the outside when rotated - State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived]) - Calculate units for k =kg s^-2 - Calculate k/m (i.e. the gradient.) (they gave units of s^-2, confirming previous answer.) - How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.) - Experiment for R, F and v using video camera and ruler.
3) Gravity Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km - Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.) - Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.) - 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.) - Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg]) - The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta). 45mA of 130keV electrons for 1.6s. - Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x10-3)(1.6)/(1.6x10-19)=4.5x10^17 electrons) - Calculate wavelength. (E=130keV=2.08x10-14J. E=hc/wavelength->wavelength=9.56x10-12 m) Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^-3[?] - Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x10-14)=9360 J. E=mc(theta)->m=E/c(theta)=(9360)/(4200)(27-17)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs-1. volume per second=(0.139)/1000= 1.39x10-4 m^3 s^-1 [Not entirely sure about this one due to forgetting the density.]
for the first part of 2) the direction of the springs acceleration and extension were oppositely directed, this was the first reason for SHM
first part of 3) was weird, I just calculated mass of marks first then used that for the next parts
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
I was joking before but I think I may have actually missed it! Whenn you say its Q3 I pressume thats not the actual Q number as the long answer Questions started at Q15 or something? Oh well hopefully I'm just blocking the pain of rememebring wrong answers from my brain
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
Have they increased the time for the G485 paper. Because I did it last year and I'm retaking this year and every paper so far has beem 1h 45mins but the place where I am doing it says 120mins (2h). Is it possible the college just gave extra time?
Have they increased the time for the G485 paper. Because I did it last year and I'm retaking this year and every paper so far has beem 1h 45mins but the place where I am doing it says 120mins (2h). Is it possible the college just gave extra time?
they've been 2 hours for a few years now I'm pretty sure.