AEA Preparation Thread 30 June 2017

Original post by nathanmcg

In(4/3) - 4/15. Anyone for last part of question 6?

I got ln(3/4) - 4/15, pretty sure it was that because I remember double checking the limits and getting ln(9/12) which then cancelled

Reply 42

Original post by Lambo1999

I got ln(3/4) - 4/15, pretty sure it was that because I remember double checking the limits and getting ln(9/12) which then cancelled

I got In(2) - In(3/2)

Reply 43

Original post by nathanmcg

Yesssss and p and q were 4 and 1 (or other way round) and y=6x-16 ???

Agreeing with all these answers! Yay!

Posted from TSR Mobile

Reply 44

Original post by Lambo1999

I got ln(3/4) - 4/15, pretty sure it was that because I remember double checking the limits and getting ln(9/12) which then cancelled

I got ln(4/3)-4/15

Posted from TSR Mobile

Reply 45

Did anyone manage to do the last part of the triangle question?

Posted from TSR Mobile

Reply 46

Original post by Lambo1999

I got ln(3/4) - 4/15, pretty sure it was that because I remember double checking the limits and getting ln(9/12) which then cancelled

You forgot must've forgotten the minus sign that was hanging outside the integral as In(3/2) - In(2) = In(3/4)

Reply 47

Original post by LaurenLovesMaths

Did anyone manage to do the last part of the triangle question?

Posted from TSR Mobile

As soon as I read that question I skipped it 😂😂😂

Reply 48

Original post by nathanmcg

I got In(2) - In(3/2)

I ended up with ln(3/2) - ln(2), did you do [t] - [t]?

Reply 49

Original post by nathanmcg

You forgot must've forgotten the minus sign that was hanging outside the integral as In(3/2) - In(2) = In(3/4)

I didn't end up with a minus sign on the integral.... What were your partial fractions?

Reply 50

Original post by Lambo1999

I ended up with ln(3/2) - ln(2), did you do [t] - [t]?

I put x back in the integral and did it with 9 and 1

Reply 51

Original post by Lambo1999

I didn't end up with a minus sign on the integral.... What were your partial fractions?

No the integral in part b, the substitution was x+3=1/t so dx = minus 1/t^2 and the minus stays there throughout the integration.

Reply 52

Original post by nathanmcg

No the integral in part b, the substitution was x+3=1/t so dx = minus 1/t^2 and the minus stays there throughout the integration.

Ah okay, I'm pretty sure I cancelled that minus out somewhere but I'm not too sure now😂😂

Reply 53

Original post by Lambo1999

Ah okay, I'm pretty sure I cancelled that minus out somewhere but I'm not too sure now😂😂

You had the right numbers just different signs, defo get most the marks

Reply 54

A Slice of Pi

Glad to see people in general enjoyed it. I'll post an unofficial mark scheme and predicted boundaries when I can get hold of the paper. If anyone has a copy they can get some pictures of and PM to me I can get started.

Reply 55

Art of Deception

Original post by A Slice of Pi

Thanks

I have a question. I had 10 minutes left and well I might have doodled a bit at the end of the paper but I crossed it out. I was just drawing shapes because I checked over my paper 3 times!! Will i lose marks?

Reply 56

A Slice of Pi

Original post by Art of Deception

Thanks

Of course not. Don't worry.

Reply 57