Trigonometry Question - Area of a Triangle

In the triangle XYZ, XY = 4.6 cm and YZ = 6.9 cm. The area of the triangle is 7.3cm^2. Find two possible values for ∠XYZ.

I've figured out one possible angle using the formula for the area of a triangle (27.4° ) but don't quite know how to get a second solution.

I'd be really grateful for some tips!

Thanks!

Without seeing your working, I presume you got to the stage where you had sin x = something, and then just found the inverse sine.

Note that sin x = sin (180 - x).

The sine graph is symmetrical about x= 90.

So if x is a solution to sin x = something, then 180-x is another solution.