The Student Room Group

Confused with units

I've come across a question that seems like it should be relatively easy, but I've changed the numbers so no one gives me the actual answer and I can work it out for myself. Here's the question:

If 0.2cm³ of oil spreads 60m², how thick is the oil layer?


I feel like you would have to convert the 0.2 into and then divide it? But I'm not really sure, and if you do have to do the conversion then I'm not sure how to actually do that
0.2 is a volume (convert it to m3), 60 is an area. Divide former by latter to get a thickness

Another hint: after conversion, the number to be divided is even smaller than 0.2
(edited 6 years ago)
Reply 2
Original post by shawn_o1
0.2 is a volume (convert it to m3), 60 is an area. Divide former by latter to get a thickness


To convert cm³ to would you just divide by 100?
Volume=length×width×heightVolume = length \times width \times height

Therefore,

Volume=area×heightVolumeArea=HeightVolume = area \times height \Rightarrow \frac{Volume}{Area} = Height

Yes you're correct, as long as your units are consistent then it should be fine.
(edited 6 years ago)
Original post by Amefish
To convert cm³ to would you just divide by 100?


You divide it by 1003
Original post by Amefish
To convert cm³ to would you just divide by 100?


You're dealing with a cubic unit so 0.21003=km3\frac{0.2}{100^{3}} = km^{3}
Reply 6
Original post by ManLike007
You're dealing with a cubic unit so 0.21003=km3\frac{0.2}{100^{3}} = km^{3}


Wait so how do I get to m³? When I get to m³, is it ok dividing that number by to get the thickness of the oil?

So confusing! And what units would the thickness be in?
Original post by Amefish
I've come across a question that seems like it should be relatively easy, but I've changed the numbers so no one gives me the actual answer and I can work it out for myself. Here's the question:



I feel like you would have to convert the 0.2 into and then divide it? But I'm not really sure, and if you do have to do the conversion then I'm not sure how to actually do that


You're completely correct about the general method, it seems like you just need to work out the conversion. The way I think about it is this:

1 m3 m^3 is 1m by 1m by 1m. This is the same as 100cm by 100 cm by 100cm which is 1003m3 100^3 m^3 . Therefore the conversion is 1:1003 1:100^3 .
Original post by Amefish
Wait so how do I get to m³?


cm3cm^{3} to m3m^{3} you just divide by 1003100^{3}

Original post by Amefish
When I get to m³, is it ok dividing that number by to get the thickness of the oil?

So confusing! And what units would the thickness be in?


Yes, remember the equation, VolumeArea=Thickness\frac{Volume}{Area} = Thickness (or height I guess), now in terms of units you get m3m2=m\frac{m^{3}}{m^{2}}=m therefore your unit for thickness is mm
Reply 9
Original post by ManLike007
cm3cm^{3} to m3m^{3} you just divide by 1003100^{3}



Yes, remember the equation, VolumeArea=Thickness\frac{Volume}{Area} = Thickness (or height I guess), now in terms of units you get m3m2=m\frac{m^{3}}{m^{2}}=m therefore your unit for thickness is mm


Thanks a lot! I'll probably have some more questions in the maths forum soon, I'm preparing for my first uni lecture and I haven't done maths since GCSE :frown:
Reply 10
@ManLike007 is this right?


0.2cm3100cm3=2x107m3\frac{0.2cm^{3}}{100cm^{3}} = 2x10^{-7}m^{3}

2x107m360m2=3.3˙x109m\frac{2x10^{-7}m^{3}}{60m^{2}} = 3.\dot{3}x10^{-9}m
Original post by Amefish
@ManLike007 is this right?


0.2cm3100cm3=2x107m3\frac{0.2cm^{3}}{100cm^{3}} = 2x10^{-7}m^{3}

2x107m360m2=3.3˙x109m\frac{2x10^{-7}m^{3}}{60m^{2}} = 3.\dot{3}x10^{-9}m


Yes that seems about right. Also in the first line, it's 1003cm3100^{3}cm^{3}, probably you forgot to write that.

If you're wondering how to write ×\times and not xx, it's just \times, just a little advice :smile:
(edited 6 years ago)
Reply 12
Original post by ManLike007
Yes that seems about right. Also in the first line, it's 1003cm3100^{3}cm^{3}, probably you forgot to write that.

If you're wondering how to write ×\times and not xx, it's just \times, just a little advice :smile:

Also, are there a specific limit of significant figures you're allowed to write as your final answer rather than recurring?


Thank you! I only just discovered the realms of LaTeX :tongue: in my actual answer I have converted it to nm and there are no recurring decimals, it's just because I changed the numbers for TSR :smile: there's no note about significant figures, but I'd assume it's 3.

Also I was wondering if you could help me with something else?

I know that 104m2=2.4710^{4}m^{2} = 2.47 acres so if I do:

1042.47\frac{10^{4}}{2.47}

Would that give me the m or the in one acre?
Original post by Amefish
Thank you! I only just discovered the realms of LaTeX :tongue: in my actual answer I have converted it to nm and there are no recurring decimals, it's just because I changed the numbers for TSR :smile: there's no note about significant figures, but I'd assume it's 3.

Also I was wondering if you could help me with something else?

I know that 104m2=2.4710^{4}m^{2} = 2.47 acres so if I do:

1042.47\frac{10^{4}}{2.47}

Would that give me the m or the in one acre?


Yes that would give you one acre in m2m^{2}

Just to explain,

[104]÷2.47[10^{4}] \div 2.47

1042.47=2.472.47\frac{10^4}{2.47} = \frac{2.47}{2.47}

4050m2=14050m^{2} = 1 acre (to 3 sig. figs)

Generally acres is a unit for land area so it'll never be in metre. It's quite to hard say why the units don't change, it's just regular division really unless you choose to change the power of ten i.e 1×109m1nm1 \times 10^{-9}m \equiv 1nm
(edited 6 years ago)
Reply 14
@ManLike007 it seems I got the complete wrong answer. Super confused right now!
Original post by Amefish
@ManLike007 it seems I got the complete wrong answer. Super confused right now!


Could you be a bit more specific by any chance?
Reply 16
Original post by ManLike007
Could you be a bit more specific by any chance?


I'm just going to see if I can work it out again so I can explain what went wrong
Reply 17
Original post by ManLike007
Could you be a bit more specific by any chance?


Basically this is a whole different approach.

area×height=volume area \times height = volume

So.. using "t" to mean thickness...

60×t=volume60 \times t = volume

cm3m3=1×106 cm^{3} \Rightarrow m^{3} = 1 \times 10^{-6}

So get the amount of oil..

0.2×106 0.2 \times 10^{-6} or.. 2×1072 \times 10^{-7}

0.2×10660=thickness=3.3˙×109 \frac {0.2 \times 10^{-6}}{60} = thickness = 3.\dot{3} \times 10^{-9}

The numbers are a bit messy here because I changed them for TSR, but this is the general method
Original post by Amefish
Basically this is a whole different approach.

area×height=volume area \times height = volume

So.. using "t" to mean thickness...

60×t=volume60 \times t = volume

cm3m3=1×106 cm^{3} \Rightarrow m^{3} = 1 \times 10^{-6}

So get the amount of oil..

0.2×106 0.2 \times 10^{-6} or.. 2×1072 \times 10^{-7}

0.2×10660=thickness=3.3˙×109 \frac {0.2 \times 10^{-6}}{60} = thickness = 3.\dot{3} \times 10^{-9}

The numbers are a bit messy here because I changed them for TSR, but this is the general method


So what’s wrong here? This is the same as yesterday’s answer. The method is the same as well, we both used the general equations
Reply 19
Original post by ManLike007
So what’s wrong here? This is the same as yesterday’s answer. The method is the same as well, we both used the general equations


Oh god, you're right! My answer for the actual question is completely different to what it should be! I must not have followed the method properly yesterday :colondollar::colondollar:

Quick Reply

Latest