Hi, can someone help me on question 1 part b (vi) and part d(i). Please and thank you
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Here's the answer for the first few questions before question 1 part (vi). I just couldn't understand how to get the answer for that and for the balancing equation, can someone teach me how. I tried balancing the oxidation number but still couldn't get it
No, i'm asking for question b last part, calculate the mass of copper that could be dissolved
Oh, sorry, I misread
From part v) we have figured out that of the 1.5M of Fe3+, 0.6 M has been converted in Fe2+.
This means that the concentration of Fe3+ in the remaining mixture is 0.9M
To know the amount of copper that can react with this 100 cm^3 of this mixture. a) moles of Fe3+ in 100 cm^3 = 0.9 x 0.1 = 0.09 moles b) moles of copper that will react (based on the first equation) = 0.09/2 = 0.045 c) mass of copper = 0.045 x Ar of copper
From part v) we have figured out that of the 1.5M of Fe3+, 0.6 M has been converted in Fe2+.
This means that the concentration of Fe3+ in the remaining mixture is 0.9M
To know the amount of copper that can react with this 100 cm^3 of this mixture. a) moles of Fe3+ in 100 cm^3 = 0.9 x 0.1 = 0.09 moles b) moles of copper that will react (based on the first equation) = 0.09/2 = 0.045 c) mass of copper = 0.045 x Ar of copper
I see! Thanks so much! Would you mind helping me on part d(i)? I couldn't balance the equation