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Original post by alow
Why not just AgNCO?
Are you sure your answer is wrong?
Are you sure your answer is wrong?
I'm wondering why is that not the answer too. But the one i wrote is exactly the answer on the marking scheme
Original post by Snowie9
I'm wondering why is that not the answer too. But the one i wrote is exactly the answer on the marking scheme
It's a suggest question so I bet you would get the marks for either, as both can be linear.
Original post by alow
Why not just AgNCO?
Are you sure your answer is wrong?
Are you sure your answer is wrong?
AgNCO is not a complex and not linear.
Original post by TutorsChemistry
AgNCO is not a complex and not linear.
That's irrelevant. Unless the specific example was taught, there's no reason for an A Level student to not think AgNCO is a linear complex.
Original post by alow
That's irrelevant. Unless the specific example was taught, there's no reason for an A Level student to not think AgNCO is a linear complex.
Ar A level students should know that linear complexes have 2 ligands.
It is always relevant to answer the question and not just pick some words from the question, ignoring what isn't liked.
Original post by TutorsChemistry
Ar A level students should know that linear complexes have 2 ligands.
It is always relevant to answer the question and not just pick some words from the question, ignoring what isn't liked.
It is always relevant to answer the question and not just pick some words from the question, ignoring what isn't liked.
Original post by Snowie9
I see thanks! So for tetrahedral there's four?
Yes. Also 4 in square planar.
6 in octohedral.
Usually when questioning about complex shapes the ligand will be monodentate, like your example ligand.
Just be aware to watch for polydentate ligands.
Original post by TutorsChemistry
Yes. Also 4 in square planar.
6 in octohedral.
Usually when questioning about complex shapes the ligand will be monodentate, like your example ligand.
Just be aware to watch for polydentate ligands.
6 in octohedral.
Usually when questioning about complex shapes the ligand will be monodentate, like your example ligand.
Just be aware to watch for polydentate ligands.
I see. How do you write the charge of the complex?
Put a square bracket around the entire formula, and the charge after the closing bracket
Original post by TutorsChemistry
Put a square bracket around the entire formula, and the charge after the closing bracket
The table or the stability constant part?
Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
Original post by TutorsChemistry
The table or the stability constant part?
Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
The table. I see it now based on what you told me earlier but i do not understand complex D. I know the ligand is neutral and therefore the charge is +2 but why the ligand have to be 3?
Original post by Snowie9
The table. I see it now based on what you told me earlier but i do not understand complex D. I know the ligand is neutral and therefore the charge is +2 but why the ligand have to be 3?
For D the ligand isn't neutral. It has a 2- charge per ion.
This ligand is bidentate, so forms 2 coordinate bonds per ligand to the iron ion. The coordination number for iron in this complex is 6 (3 ligands providing 2 coordinate bonds each).
The ligand is the ion of the dicarboxylic acid ethandioic acid (also called oxalic acid).
Original post by TutorsChemistry
For D the ligand isn't neutral. It has a 2- charge per ion.
This ligand is bidentate, so forms 2 coordinate bonds per ligand to the iron ion. The coordination number for iron in this complex is 6 (3 ligands providing 2 coordinate bonds each).
The ligand is the ion of the dicarboxylic acid ethandioic acid (also called oxalic acid).
This ligand is bidentate, so forms 2 coordinate bonds per ligand to the iron ion. The coordination number for iron in this complex is 6 (3 ligands providing 2 coordinate bonds each).
The ligand is the ion of the dicarboxylic acid ethandioic acid (also called oxalic acid).
Are you talking about complex D? D has Nickel
Sorry, my mistake.
The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
For D: Coordination number is 6 - 6 lone pairs, therefore it is an octahedral complex.
H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
Original post by TutorsChemistry
Sorry, my mistake.
The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
I see! Thanks!!
Original post by ChemistryGuy1998
For D: Coordination number is 6 - 6 lone pairs, therefore it is an octahedral complex.
H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
Thank you! I got it now
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