How to calculate the enthalpy of lattice formation of silver iodide using the data?
The data given is: Ag+(s) --> Ag+(aq) + I- (aq) = +112
Ag+(g) --> Ag+(aq) = -464
I-(g) --> I-(aq) = -293
Keep getting the answer -869kj mol-1 but not sure if its correct.
Ag+(g) --> Ag+(aq) = -464
I-(g) --> I-(aq) = -293
Keep getting the answer -869kj mol-1 but not sure if its correct.
(edited 6 years ago)
Original post by sumayyah99
The data given is: Ag+(s) --> Ag+(aq) + I- (aq)
Ag+(g) --> Ag+(aq)
I-(g) --> I-(aq)
Keep getting the answer -869kj mol-1 but not sure if its correct.
Ag+(g) --> Ag+(aq)
I-(g) --> I-(aq)
Keep getting the answer -869kj mol-1 but not sure if its correct.
You haven't given any information
yeah didn't realise it saved without me writing all the figures lol
Original post by SGHD26716
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