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How can i simpliy this expression further?

ln(z)+3ln(1-z)+3ln(y)+ln(1-y)+2ln(x)+2ln(1-x)

where z= exp(A)/(1+exp(A))
where y=exp(A+C)/(1+exp(A+C))
where x= exp(A+B)/(1+exp(A+B))
Original post by Sxphie_xx
ln(z)+3ln(1-z)+3ln(y)+ln(1-y)+2ln(x)+2ln(1-x)

where z= exp(A)/(1+exp(A))
where y=exp(A+C)/(1+exp(A+C))
where x= exp(A+B)/(1+exp(A+B))


You can turn it all into a single ln, then substitute.

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