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Maths AS surd question help please

Solve the equation:
10+x root 8= 6x divided by root 2
Give your answer in the form a root b where a and b are integers
Are my workings correct?
10+ x root 8= 6x divided by root 2
10+ x root 2 root 4= 6x divide root 2
10+2x=6x
10=4x
10/4=x
5/2=x
X= 2.5
When I substitute it in it doesn't equate
Many thanks for your help
Reply 1
Avatar for Notnek
Notnek
21
Original post by Musicanor
Solve the equation:
10+x root 8= 6x divided by root 2
Give your answer in the form a root b where a and b are integers
Are my workings correct?
10+ x root 8= 6x divided by root 2
10+ x root 2 root 4= 6x divide root 2
10+2x=6x
10=4x
10/4=x
5/2=x
X= 2.5
When I substitute it in it doesn't equate
Many thanks for your help

Can you please rewrite your question/working using brackets? It's very hard to read.

Also, please post questions in the maths forum in future and you'll get a faster response. I've moved this one for you :smile:
Original post by Musicanor
Solve the equation:
10+x root 8= 6x divided by root 2
Give your answer in the form a root b where a and b are integers
Are my workings correct?
10+ x root 8= 6x divided by root 2
10+ x root 2 root 4= 6x divide root 2
10+2x=6x
10=4x
10/4=x
5/2=x
X= 2.5
When I substitute it in it doesn't equate
Many thanks for your help

It is not asking you to solve the equation but to write it in surd form
Reply 3
Avatar for Notnek
Notnek
21
Original post by aspen fernandes
It is not asking you to solve the equation but to write it in surd form

The question is asking to solve the equation and write the solution in surd form.
x root 2 root 4=2x


Root2 times root4 is 2root2 not 2
Reply 5
Avatar for Notnek
Notnek
21
Original post by Queenie123
x

I had to remove your post since it was a full solution, which is against the maths forum rules. Please read the posting guidelines at the top of the forum :smile:
Oh I didn’t realise sorry:smile:
Original post by Notnek
I had to remove your post since it was a full solution, which is against the maths forum rules. Please read the posting guidelines at the top of the forum :smile:
Original post by Musicanor

10+ x root 2 root 4= 6x divide root 2
10+2x=6x


Check your working here:smile:
Original post by Musicanor
Solve the equation:
10+x root 8= 6x divided by root 2
Give your answer in the form a root b where a and b are integers
Are my workings correct?
10+ x root 8= 6x divided by root 2
10+ x root 2 root 4= 6x divide root 2
10+2x=6x
10=4x
10/4=x
5/2=x
X= 2.5
When I substitute it in it doesn't equate
Many thanks for your help

this is as far as i got i don't know if it's right
10+x root 8 = 6x/root 2
10+x root 4 root 2= 6x/root2
10+2xroot2=6x/root2 * root2/root2
10+2xroot2=6xroot2/2
20+x root 2
maybe correct me if I am wrong pleased anyone
Reply 9
Avatar for Musicanor
Musicanor
OP
9
Original post by aspen fernandes
this is as far as i got i don't know if it's right
10+x root 8 = 6x/root 2
10+x root 4 root 2= 6x/root2
10+2xroot2=6x/root2 * root2/root2
10+2xroot2=6xroot2/2
20+x root 2
maybe correct me if I am wrong pleased anyone


Okay thanks everyone :smile:
Original post by aspen fernandes
this is as far as i got i don't know if it's right
10+x root 8 = 6x/root 2
10+x root 4 root 2= 6x/root2
10+2xroot2=6x/root2 * root2/root2
10+2xroot2=6xroot2/2
20+x root 2
maybe correct me if I am wrong pleased anyone


what did you do there?
Reply 11
Avatar for smaiu
smaiu
11
Well I got 5 root 2 as my answer
I multiplied everything by root 2 which gave 10 root 2 + 4x = 6x
I then took away 4x which gave me 10 root 2 = 2x
I then divided everything by two which gave me 5 root 2 = x
What i got aswell
Original post by KarthikK123
What i got aswell


Original post by begbie68
Your mistake is on the 3rd line.
should be
10root2 + 4x = 6x

You need to multiply your 2nd line by root2 ..... every term is multiplied


Old thread.
Such an old thread but the answers 5\root2 for anyone wondering. Hope everyone's doing well :')

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