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image.jpgimage.jpgMaths questions need help
(edited 6 years ago)
Reply 1
Avatar for yemenia16
yemenia16
OP
15
Thank you
image.jpg512.2KB
Sorry, I don't know. I'll wait with you until someone gives the answer... :smile:
Reply 3
Avatar for yemenia16
yemenia16
OP
15
Help
Reply 4
Avatar for Nin500a
Nin500a
9
Give me a minute ill have a go
Original post by yemenia16
😩😩😩

Not like I know anything, but can we have ALL of your workings please?
Reply 6
Avatar for yemenia16
yemenia16
OP
15
I haven’t tried it 😅 but it looks hard my teacher was struggling to answer it 😭😂
Reply 7
Avatar for Nin500a
Nin500a
9
Sorry im stuck, thats really hard is that gcse or a level????
Reply 8
Avatar for yemenia16
yemenia16
OP
15
Yh alevel
Original post by yemenia16
I haven’t tried it 😅 but it looks hard my teacher was struggling to answer it 😭😂


Sorry, this is not how TSR works, try it first and come back later.
Read this as well:https://www.thestudentroom.co.uk/showthread.php?t=4927300
Reply 10
Avatar for yemenia16
yemenia16
OP
15
04BE7CB7-A7C0-4F5E-82CD-86C5C48E9011.jpg.jpeg ???
Reply 11
Avatar for NatKH
NatKH
13
Area of a trapezium = 1/2h(a+b)
50 = 1/2(2x(x + x+10))
50 = x(2x +10)
50 = 2x^2 + 10x
2x^2 +10x - 50 = 0
x^2 + 5x - 25 = 0
So if you put this into the quadratic formula (-b + root(b^2 - 4ac))/2a
You should get x = (-5+5root(5))/2
You then substitute this value into the height 2x to get your answer.
Make sense?
I have the same textbook and it comes with an online "Active Book" which has a "solution bank" with full worked solutions for every question in the book. Details of how to access this are on the inside of the front cover :smile:

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