GCSE Maths question help (Histograms)

Can someone help me on this question please? like walk through it, because the mark scheme doesn't help at all. In all the worked solutions I've seen, the areas are found out using random numbers? I don't have a clue what to do. Thanks.

(These are the solutions I'm talking about, Idk where the numbers are coming from)

Question 8 on these:
http://mathstallis.weebly.com/uploads/1/4/8/3/14836922/gcse_prac_2h_ws.pdf
http://homework.m34maths.com/files/documents/GCSE-Prac1-Paper-2H-Solutions.pdf

Reply 1

Notnek

21

Original post by THEgurlxo

Can someone help me on this question please? like walk through it, because the mark scheme doesn't help at all. In all the worked solutions I've seen, the areas are found out using random numbers? I don't have a clue what to do. Thanks.

(These are the solutions I'm talking about, Idk where the numbers are coming from)

Question 8 on these:
http://mathstallis.weebly.com/uploads/1/4/8/3/14836922/gcse_prac_2h_ws.pdf
http://homework.m34maths.com/files/documents/GCSE-Prac1-Paper-2H-Solutions.pdf

Frequency on a histogram is the area. The median is at halfway point of the frequency so you need to first find the total area then divide it by 2. Then you need to find how far along the x-axis you need to go to get this half area.

This is often a hard topic for GCSE students. If you still need help tomorrow then let us know and it can be explained to you in more detail.

Reply 2

THEgurlxo

OP

10

I still dont understand. How can i work out the area if there are no numbers on the vertical axis?

Reply 3

Aweevee

11

frequency density= frequency/class width

Reply 4

THEgurlxo

OP

10

i still dont get it, there's only one set of numbers

Reply 5

Notnek

21

Original post by THEgurlxo

I still dont understand. How can i work out the area if there are no numbers on the vertical axis?

You can count the squares and use that as your scale. You don't need to find the actual frequency (that is impossible because of no scale on the y-axis as you said) but you need to find where half the area lies. And this can be done whatever the scale on the y-axis is.