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Hard logs

5^3w-1 = 4^250
5^(3w-1) = 4^250

I've tried doing:

log(5)^3w-1 = log(4)^250
log (5)^3w-1 - log (4)^250 = 0
log (5^3w-1 / 4^250) = 0

Don't know where to go from here
Original post by SmartFailure
5^(3w-1) = 4^250

I've tried doing:

log(5)^3w-1 = log(4)^250
log (5)^3w-1 - log (4)^250 = 0
log (5^3w-1 / 4^250) = 0

Don't know where to go from here


Go back to step one. log⁡(53w−1)=(3w−1)log⁡(5)\log(5^{3w-1})=(3w-1)\log(5)
is this right:

(3w-1)log(5) = 250log(4)

3w-1 = 250xlog(4) / log(5)

3w - 1 = 215.33
3w = 216.33
w = 72.11
Original post by SmartFailure
is this right:

(3w-1)log(5) = 250log(4)

3w-1 = 250xlog(4) / log(5)

3w - 1 = 215.33
3w = 216.33
w = 72.11


Give the exact form, unless it asks for the approximation. Overall, yes that's right.
The only way to calculate this is: 250xlog(4) / log(5) is by calculator right?
Original post by SmartFailure
The only way to calculate this is: 250xlog(4) / log(5) is by calculator right?


No need, just leave it in its exact form.
Alright thanks for the help

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