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Natural logs AS maths

find in terms of the natural logarithm the exact solution to the equation e^3-2x =10.
Original post by mathsaerospace
find in terms of the natural logarithm the exact solution to the equation e^3-2x =10.


I assume that's e3−2x=10e^{3-2x}=10

Well what's the obvious first step? Have you tried to solve it?
Original post by mathsaerospace
I had got a very similar answer, but the textbook answer is different, hence we're probably wrong.


What does the texbook say?
Original post by (NaCl)-ty
What does the texbook say?


X= In[SQRT(e^3/10)], is the textbook answer
Original post by mathsaerospace
X= In[SQRT(e^3/10)], is the textbook answer


and what was your answer?

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