Doing Parametric differentiation.....finding t problem

Original post by joyoustele

How would i get t from this?

-2t+t^2(1+t)^2=0

Well there is one obvious root, and one not so obvious root.

Reply 2

Original post by RDKGames

Well there is one obvious root, and one not so obvious root.

t=0

and

t=-2

but i dont know how to get this

Reply 3

Original post by joyoustele

t=0

and

t=-2

but i dont know how to get this

-2 is clearly not a root. Means your equation is wrong

Reply 4

Original post by joyoustele

t=0

and

t=-2

but i dont know how to get this

Please post the original question. It looks like either you've made a mistake in your working or the equation you posted in your OP is wrong.

Reply 5

Original post by RDKGames

-2 is clearly not a root. Means your equation is wrong

k, I went wrong some where then, Thanks :smile:

Reply 6

the bear

factorise:

t { -2 + t ( 1 + t )² } = 0

then have a think...

Reply 7

Original post by Notnek

Please post the original question. It looks like either you've made a mistake in your working or the equation you posted in your OP is wrong.

Thanks, worked it out, silly mistake from me

Reply 8

Trying to solve

t(1+t)^2=2

without numerical methods is possible but looks like a nightmare...

Luckily this isn't something that the OP has to do :smile:

Reply 9

Original post by the bear

factorise:

t { -2 + t ( 1 + t )² } = 0

then have a think...

I've had a think, now what :smile:

Reply 10

Original post by Notnek

Trying to solve

t(1+t)^2=2

without numerical methods is possible but looks like a nightmare...

Luckily this isn't something that the OP has to do :smile:

lol

Reply 11

Original post by Notnek

Trying to solve

t(1+t)^2=2

without numerical methods is possible but looks like a nightmare...

Luckily this isn't something that the OP has to do :smile:

Just slam the cubic formula on it, what’s so difficult?

Reply 12

Original post by RDKGames

Just slam the cubic formula on it, what’s so difficult?

Yes I suppose you'd need to resort to using the cubic formula here because other methods are too nasty.

Reply 13

Original post by Notnek

Yes I suppose you'd need to resort to using the cubic formula here because other methods are too nasty.

Just solved it in my head using it.

I’d tell you but this post is too narrow to contain it.

Reply 14