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Solve x^2/3 - 17x^1/3 + 16= 0

How would I go about solving this?
This is simply a quadratic. This is u^2 - 17u + 16 =0 --> (u-1)(u-16) = 0. U = 1 or 16.

And here we let u = x^1/3 so x=...?
Reply 2
Original post by thekidwhogames
This is simply a quadratic. This is u^2 - 17u + 16 =0 --> (u-1)(u-16) = 0. U = 1 or 16.

And here we let u = x^1/3 so x=...?


Ah I see, so x is either 1 or 4096. Cheers man.
Original post by BMart
Ah I see, so x is either 1 or 4096. Cheers man.


No problem.

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