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Maths gcse question

How would you rearrange this? To make x the subject.
y = x+5 over 2x-2?
(edited 6 years ago)
Reply 1
Avatar for Patpsbl
Patpsbl
10
y(2x-2)=x+5

2xy-2y=x+5

2xy-2y-5=x
Reply 2
Avatar for Maths1210
Maths1210
OP
10
Original post by Patpsbl
y(2x-2)=x+5

2xy-2y=x+5

2xy-2y-5=x


How did you get this?
y(2x-2)=x+5

2xy-2y=x+5 (expand brackets)

2xy-x=2y+5 (add 2y and subtract x from both sides)

x(2y-1)=2y+5 (factorise out x)

x=2y+5 over 2y-1 (divide by 2y+1)
Original post by aesthete1
(divide by 2y+1)


sorry should say divide by 2y-1
Reply 5
Avatar for Maths1210
Maths1210
OP
10
Original post by aesthete1
sorry should say divide by 2y-1


Thanks but where did you get the y(2x-2) = x+5
Original post by Maths1210
Thanks but where did you get the y(2x-2) = x+5


multiply both sides by 2x-2
Reply 7
Avatar for tdag
tdag
16
Original post by Maths1210
How would you rearrange this? To make x the subject.
y = x+5 over 2x-2?


y = (x+5)/(2x-2)

multiply both sides by (2x-2):

y(2x-2) = x+5

expand:

2xy-2y = x+5

rearrange:

2xy-x = 2y+5

factorise left hand side:

x(2y-1) = 2y+5

divide both sides by (2y-1):

x = (2y+5)/(2y-1)
Reply 8
Avatar for tdag
tdag
16
Original post by Patpsbl
y(2x-2)=x+5

2xy-2y=x+5

2xy-2y-5=x


This is wrong.
Reply 9
Avatar for Maths1210
Maths1210
OP
10
Original post by aesthete1
multiply both sides by 2x-2


Oh I get it now thank you.
Original post by tdag
This is wrong.


probably, I haven't done algebra in 2 years

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