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c3 help




part b)

I know what to do but I'm having a nightmare rearranging to find a nice equation for the normal as such in the mark scheme.

here's my working so far
(edited 6 years ago)
FvDrgOK.png68.3KB
Original post by BTAnonymous
http://www.physicsandmathstutor.com/a-level-maths-papers/c3-aqa/

June 2016 q 4. b)

I know what to do but I'm having a nightmare rearranging to find a nice equation for the normal as such in the mark scheme.
Move to the Maths study help forum.:wink:
bump
Original post by BTAnonymous
bump
The thread has literally been here 40 mins, have a bit of patience.:wink:
Original post by 04MR17
The thread has literally been here 40 mins, have a bit of patience.:wink:


Then you can deduce that i'm an extremely impatient person. :smile:
Original post by BTAnonymous
Then you can deduce that i'm an extremely impatient person. :smile:


[video="youtube;273eSvOwpKk"]https://www.youtube.com/watch?v=273eSvOwpKk[/video]
Original post by 04MR17
[video="youtube;273eSvOwpKk"]https://www.youtube.com/watch?v=273eSvOwpKk[/video]


So long since I last heard this!
@BTAnonymous, would you like to show your working so far?
Original post by 04MR17
@BTAnonymous, would you like to show your working so far?


can't embed it onto my original post for some reason.


(edited 6 years ago)
Which exam board is this?
Original post by BTAnonymous
can't embed it onto my original post for some reason.




Paste this in.:wink:

[noparse][/noparse]
Original post by VictiniCup
Which exam board is this?


aqa old spec
Original post by BTAnonymous



part b)

I know what to do but I'm having a nightmare rearranging to find a nice equation for the normal as such in the mark scheme.

here's my working so far


I can't follow what you've done.

find dy/dx. Plug in the x value at p for the gradient of the tangent.

Flip and times by -1 for the gradient of the normal.

use y-y1=m(x-x1) to find the equation of the normal.

Plug in the zeroes to find where it crosses the axes.

use 1/2bh to find the area of the triangle.
Original post by NotNotBatman
I can't follow what you've done.

find dy/dx. Plug in the x value at p for the gradient of the tangent.

Flip and times by -1 for the gradient of the normal.

use y-y1=m(x-x1) to find the equation of the normal.

Plug in the zeroes to find where it crosses the axes.

use 1/2bh to find the area of the triangle.


was missing this. ty
Original post by NotNotBatman
I can't follow what you've done.

find dy/dx. Plug in the x value at p for the gradient of the tangent.

Flip and times by -1 for the gradient of the normal.

use y-y1=m(x-x1) to find the equation of the normal.

Plug in the zeroes to find where it crosses the axes.

use 1/2bh to find the area of the triangle.


oh im an idiot. I forgot to plug in the x value for my gradient of the normal. smh.
Original post by BTAnonymous
oh im an idiot. I forgot to plug in the x value for my gradient of the normal. smh.


Did you manage to get the answer?
Original post by NotNotBatman
Did you manage to get the answer?


almost, however it looks like I have mine in a different form but is still numerically the same.

my form:

2e−1+e+e−3 2e^{-1} + e + e^{-3}

mark scheme:

(e2+1)2e3 \frac{(e^2 + 1)^{2}}{e^{3}}
Original post by BTAnonymous
almost, however it looks like I have mine in a different form but is still numerically the same.

my form:

2e−1+e+e−3 2e^{-1} + e + e^{-3}

mark scheme:

(e2+1)2e3 \frac{(e^2 + 1)^{2}}{e^{3}}


If the answer they are looking for is a single fraction, then you should probably write your answer as a single fraction.

Yes your answer is the same as the mark scheme, but you need to be able to convert to it otherwise you don't get the last mark.
Original post by BTAnonymous
almost, however it looks like I have mine in a different form but is still numerically the same.

my form:

2e−1+e+e−3 2e^{-1} + e + e^{-3}

mark scheme:

(e2+1)2e3 \frac{(e^2 + 1)^{2}}{e^{3}}


e^(-n) =1/(e^n)

Use this and turn it into a single fraction using the LCM.

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